Wastewater samples taken from an industrial discharge had the chemical oxygen demand (COD) concentrations below in mg/L. Determine the (a) arithmetic mean (by hand and spreadsheet), (b) median, (c) mode, and (d) standard deviation (by hand and spreadsheet). COD values: 452, 364, 415, 395
Wastewater samples taken from an industrial discharge
had the chemical oxygen demand (COD)
concentrations below in mg/L. Determine the (a)
arithmetic mean (by hand and spreadsheet), (b)
median, (c) mode, and (d) standard deviation (by
hand and spreadsheet).
COD values: 452, 364, 415, 395
Since you have posted a question with multiple subparts, we will solve the first three subparts for you. To get remaining sub - Part solved please repost the complete question and mention the subparts to be solved
COD values in ascending order,
364, 395, 415, 452
Arithmetic mean = sum of all the COD value / Number of COD
Arithmetic mean = 364 + 395 + 415 + 452 / 4
Arithmetic mean = 406 .5
b) Median, number of observation = 4 that is an even value therefore,
We will use following formula;
{n/2 th term + (n/2 + 1)th term } / 2
(2nd term + 3rd term) / 2
(395 + 415) / 2
810 / 2
Median = 405
c)
Mean – Median = 1/3(Mean – Mode)
3 Mean – 3 median = Mean – Mode
Mode = 3 Median – 2 Mean
Mode = 3*405 – 2*406.5
Mode = 1215 – 813
Mode = 403
Step by step
Solved in 3 steps with 1 images
