Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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- (a) Figure Q2(a) to (c) shows beams with different loads and supports. Derive the moment equation in each beam by using the Maccaulay Method.arrow_forward6. Use the three moment theorem to analyzo the Continuous beam shown below. Draw the shear force diayram and bending Monent diagram re B. 160 1-Sm 1.Sm Bmarrow_forward3. Find the value of El midway between the supports for the beam shown. Use the Super Position method. -5 m- 180 KN B m El = constant E = 70 GPa I = 2,340 (106) mm4 15 kN/m m-arrow_forward
- F=30 kN single load, M=34 kN.m moment and w=10 kN/m distributed load are acting on the beam whose loading condition is given in the figure. Point B is located just to the right of the application point of force F and moment M. The length L is also given as L=5 m. According to this;Question1-A) Find the support response (Dy) at point D. (Write your result in kN.)Question1-B) Find the support response (Ay) at point A. (Write your result in kN.)Question1-C) Find the shear force (VB) at point B. (Write your result in kN.)arrow_forwardFor the given beam and load a) show the correct equation of shear and bending-moment curves b) correct expression for max. the absolute value of bending moment in beam.arrow_forwardThe simply supported beam consists of a W21 x 44 structural steel wide-flange shape [E = 29,000 ksi; / = 843 in.4]. Assume that the support at D can provide resistance either up or down. For a loading of w = 6 kips/ft, determine: (a) the beam deflection VÀ at point A. (b) the beam deflection vc at point C. Assume LAB = 13 ft, LBc = 8 ft, LcD = 8 ft, LDE = 5 ft. W B Answers: (a) VA = (b) vc= LAB LBC in. in. D LCD LDEarrow_forward
- From the given simply supported beam below, determine the following: a, The shear and moment equation of each segment of the beami Use point A as reference of b. The Shear and Mament Diagram of the beam e The maximum shearand moment of the beam. d. The moment of Ihertia with respect to the neutral axls. e. The maximum flexurál stress and shear stress of the beam. I. The bending stress at point B andC * The shear stressät the mid-point of the beam. 20 kN 14 kN / m 10 KN / m A B [D] E 4 m 25 m 25 m 3 m 360 mm 80 mm 130 mm 130 mm 300 mm 90 mm 280 mmarrow_forwardDetermine the maximum bending moment for the beam shown below. Usea = 8 ft, b= 12 ft,c = 6 ft, and w= 15 kips/ft. The reaction forces for this beam areA, = 83.1 kips and Dy = 96.9 kips. В D a b Answer: Mmax = i kip-ftarrow_forwardThe beam supports the loads as shown in the figure. Using E=200 GPa, w = 16 kN/m, P = 16 kN and M = 24 kNm, L1= 3 m, L, = 5, L3= 2 m and a=35 mm. Find, a. by double integration method find the ElS at the right end of the beam b. by double integration method the maximum Elő between supports c. If w is spread over L-and L7, and P and M are interchanged, determine the midspan Eló and deflection by moment- area method. 4a W 10a M D 7aarrow_forward
- 3². A cantilever beam carries a vertical load of 150 KN at point B and uniform load of 30 KN/m from C to D., MX a. Draw Shear and Moment Diagrams. b. Using conjugate beam method, solve deflection and slope at B 150KN 4m B 4 m C 30 KN/m 7m D Assume El to be constant: E = 200,000 MPa, I = 500 x 106 mm4.arrow_forwardA simply supported beam carries a moment applied to one end as shown. El is constant. a) Calculate the support reaction forces for the beam b) Write out the M(x) equation using discontinuity functions. c) Determine the slope and deflection equations by integrating the M(x) equation as needed and using two B.C. to solve for the integration constants, C1 and C2. d) Calculate the deflection at the mid-span of the beam. e) Check: Calculate the deflection at point B (right support). A 12Aarrow_forwardThe simply supported beam shown carries a load that varies from zero at A to 48KN/m at B. Compute (a) slope of the elastic curve at A; (b) slope of the elastic curve at B; (c) deflection 4m to the right of A. EI = constant 48 kN/m 6 marrow_forward
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