Volume of HCI (mL) Volume of NaOH (mL) Temperature of HCI (°C) Temperature of mixture after reaction (°C) Temperature difference (°C) Number of joules evolved (J) (enter a positive value) Moles of H* that were neutralized (mol) Joules evolved per mole of H* (J/mol) Trial 1 50.0 50.0 27.4 31.8 4.4 Trial 2 50.0 50.0 27.4 31.8 4.4

Volume of HCI (mL) Volume of NaOH (mL) Temperature of HCI (°C) Temperature of mixture after reaction (°C) Temperature difference (°C) Number of joules evolved (J) (enter a positive value) Moles of H* that were neutralized (mol) Joules evolved per mole of H* (J/mol) Trial 1 50.0 50.0 27.4 31.8 4.4 Trial 2 50.0 50.0 27.4 31.8 4.4

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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For each of the following reactions, identify whether the reactants or the products would have more potential energy. + C(s) + 2H₂O(g) + 90.1 kJ → 2CO2(g) + 2H₂(9) CO(g) + H₂O(g) - 2CO₂(g) + 2H₂(g) + 41.2 kJ C₂H₂OH(I) + 30₂(9) - 2C0₂(g) + 3H₂O(g) C3H8(9) + 6H₂O(g) → 3CO₂(g) + 10H₂(g) Use the following to answer the next 3 questions. The smelting of iron occurs in a blast furnace, as represented by the following overall equation. Step I 3Fe2O3(s) + CO(g) - CO₂(g) + 2Fe3O4(s) A+H° = -47.2 kJ Step II Fe₂O4(s) + CO(g) - CO₂(g) + 3FeO(s) A,H+19.4 kJ Step III FeO(s) + CO(g) - CO₂(g) + Fe(s) AH = -11.0 kJ The molar enthalpy of reaction for Fe₂O3(s) in the reaction represented by Step I is Record your 3-digit answer. Include sign; do not include units. Potential Energy (kJ) AH-514.1 kJ Reactants ACH° +374.1 kJ Which steps in the above process can be represented by the following potential energy diagram? Select one: O Step II only O Steps I and III O Steps I, II and III O None of the above…
1. For the reaction: 2NH3(g) + CO2(g) (NH2)2CO(s) + H2O(g) AH = - 330 kJ Predict how each of the following changes would impact a reaction that is currently at equilibrium. That is, which way would the reaction progress in order to respond to the change in the system to regain equilibrium (use arrows to show the direction of change that would occur to return back to equilibrium). Explain your reasoning for each part.
Use arrows (up / down) to indicate the affect of each of these disturbances (stresses) on the concentration of the reactants and products in this equilibrium: 9 KJ + 2 S02 9) + 02 (9) = 2 S03 (9A disturbance affect on affect on affect on ISO2] [02] ISO3] decrease [SO2] increase [02] increase [SO3] increase pressure decrease temp Period 4 CHE
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Energy (kJ)) 4. Consider the figure shown below in answering the questions: 160 140 120 100 80 60 40 20 0 T ▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬ Progress of reaction a) What is the energy of activation, Ea for the reaction? b) What is the AE for the reaction? c) Is the reaction exothermic or endothermic? kJ kJ
Dinitrogen tetroxide partially decomposes according to the following equilibrium: N204(g) = 2NO2(g) A 1.000-L flask is charged with 0.0300 mol of N204. At equilibrium, 0.0204 mol of N204 remains. Calculate the Kc for this reaction. (Enter only the numerical value to three significant figures without units.) Answer:
Y Background Layout 1|¹234|15 8-8 H₂ Reactants Number of hydrogen atoms Number of oxygen atoms Equation 2 speaker notes Theme Transition 61 111711LTI 8|19 go H₂O Product Number of hydrogen atoms Number of oxygen atoms 1₁ Is equation 2 balanced?
Question 11 of 13 Submit What is the missing value in the table below? Reaction AH (kJ/mol) A - B -10 В — С A → C kJ/mol 1 2 3 4 6. C 7 8 +/- x 10 0 Tap here or pull up for additional resources LO
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QUESTION 6 13. Which of the following diagrams best represents the following reaction: 2H2 02 2H20 571.6 kJ Reaction Coordinate Reaction Coordinate (3) (1) Reaction Coordinate Reaction Coordinate 01 O 3 4. Click Save and Submit to save and submit. Click Save All Answers to save all answers. Potential Energy O O O O Potential Energy
302(9) = 203(g) O decreasing the volume will shift equilibrium in the direction of products O decreasing the volume will shift equilibrium in the direction of reactants no shift occurs Submit Request Answer Part B (6)o + (6)007 = (6)z007 decreasing the volume will shift equilibrium in the direction of products decreasing the volume will shift equilibrium in the direction of reactants no shift occurs Reguest Answer Submit Part C P.(g) + 50,(g) = P,010 (4) O decreasing the volume will shift equilibrium in the direction of products O decreasing the volume will shift alibrium in the direction of reactants no shift occurs Submit Reguest Answer Part D 2s0,(9) + 2H,0(g) = 2H,S(g) + 30,(g) O decreasing the volume will shift equilibrium in the direction of products decreasing the volume will shift equilibrium in the direction of reactants O no shift occurs O O