Question

Transcribed Image Text:VIII. Zeeman Effect: Bohr Magneton
Joe continued his parade of ill-advised suggestions, adjustments and "improvements" by
replacing the electromagnet coil that we used for our Zeeman Effect Lab Exercise. He mentioned
that it was really heavy and awkward and, instead, he wants us to use a new electromagnet coil
that he has made. This new coil:
Is made of nickel (NOT copper)
Has half the amount of turns
Is three times the length of the previous coil
If a current of the same magnitude is drawn through Joe's electromagnet as was drawn through
our original electromagnet, what would be the theoretical value for the magnetic field
produced by Joe's electromagnet, Bjoe, as compared to your experimental value Bexp?
Please consider:
kμNI
Bjoe L
Equation 01: Equation for calculating the magnetic field produced within a solenoid coil,
where kдo (also referred to a simply "u") is the permeability constant that depends on
the substance with which the solenoid core is made of, "N" is the number of turns in the
coil, "I" is the current within the wire and "L" is the length of coil itself.
Hcopper
Hnickel
1.256629 x 10 H/m
3.50 x 10-4 H/m
· For Bexp, use your experimental value for B from Lab 08 (Zeeman Effect - Bohr Magneton)
as your reference to find Bjoe-
There are also doubts that Joe actually fully understood the lab manual entry for the Zeeman
effect lab activity focused on the Bohr magneton. He left a note that read,
"The outer Zeeman lines in each triplet increase their distance from one another
as I Increase the current flow through the electromagnet. Something in the set-up
must be broken."
Please explain why this is, in fact, to be expected and can be accounted for by the following
equation:
HB=
he(R.-)
2BAf
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by stepSolved in 2 steps

Knowledge Booster
Similar questions
- 2. The figure below shows a metal plate with a width of w = 2 cm and a thickness of t = 0.1 cm. An electric current I = 20A is applied to it and placed in a magnetic field B in the direction shown in the figure. When the applied magnetic field is 2 tesla, the resulting Hall voltage of 4.28 V. Based on the above, determine the electron drift velocity (Vd)!arrow_forward2. A long cylindrical wire has a radius R and a uniform current density J. In terms of J, Use Ampere's law to... a) Calculate the magnetic field at a point inside the wire. b) Calculate the magnetic field at a point outside the wire. (Obviously the current density outside the wire is zero, but the B field is not!)arrow_forward