VIII. Zeeman Effect: Bohr Magneton Joe continued his parade of ill-advised suggestions, adjustments and "improvements" by replacing the electromagnet coil that we used for our Zeeman Effect Lab Exercise. He mentioned that it was really heavy and awkward and, instead, he wants us to use a new electromagnet coil that he has made. This new coil: Is made of nickel (NOT copper) Has half the amount of turns Is three times the length of the previous coil If a current of the same magnitude is drawn through Joe's electromagnet as was drawn through our original electromagnet, what would be the theoretical value for the magnetic field produced by Joe's electromagnet, Bjoe, as compared to your experimental value Bexp? Please consider: kμNI Bjoe L Equation 01: Equation for calculating the magnetic field produced within a solenoid coil, where kдo (also referred to a simply "u") is the permeability constant that depends on the substance with which the solenoid core is made of, "N" is the number of turns in the coil, "I" is the current within the wire and "L" is the length of coil itself. Hcopper Hnickel 1.256629 x 10 H/m 3.50 x 10-4 H/m · For Bexp, use your experimental value for B from Lab 08 (Zeeman Effect - Bohr Magneton) as your reference to find Bjoe- There are also doubts that Joe actually fully understood the lab manual entry for the Zeeman effect lab activity focused on the Bohr magneton. He left a note that read, "The outer Zeeman lines in each triplet increase their distance from one another as I Increase the current flow through the electromagnet. Something in the set-up must be broken." Please explain why this is, in fact, to be expected and can be accounted for by the following equation: HB= he(R.-) 2BAf

VIII. Zeeman Effect: Bohr Magneton Joe continued his parade of ill-advised suggestions, adjustments and "improvements" by replacing the electromagnet coil that we used for our Zeeman Effect Lab Exercise. He mentioned that it was really heavy and awkward and, instead, he wants us to use a new electromagnet coil that he has made. This new coil: Is made of nickel (NOT copper) Has half the amount of turns Is three times the length of the previous coil If a current of the same magnitude is drawn through Joe's electromagnet as was drawn through our original electromagnet, what would be the theoretical value for the magnetic field produced by Joe's electromagnet, Bjoe, as compared to your experimental value Bexp? Please consider: kμNI Bjoe L Equation 01: Equation for calculating the magnetic field produced within a solenoid coil, where kдo (also referred to a simply "u") is the permeability constant that depends on the substance with which the solenoid core is made of, "N" is the number of turns in the coil, "I" is the current within the wire and "L" is the length of coil itself. Hcopper Hnickel 1.256629 x 10 H/m 3.50 x 10-4 H/m · For Bexp, use your experimental value for B from Lab 08 (Zeeman Effect - Bohr Magneton) as your reference to find Bjoe- There are also doubts that Joe actually fully understood the lab manual entry for the Zeeman effect lab activity focused on the Bohr magneton. He left a note that read, "The outer Zeeman lines in each triplet increase their distance from one another as I Increase the current flow through the electromagnet. Something in the set-up must be broken." Please explain why this is, in fact, to be expected and can be accounted for by the following equation: HB= he(R.-) 2BAf