Industrial ElectronicsPlease give the step-by-step solution of the following:(a) Standard average current diode rating(b) Standard peak current diode rating(c) Transformer 2. Design a power supply by specifying their rating to the nearest standard values.220 VIBO H0 DegVrdg = 24VdcRL120 OhmEripplepk-pk = 0.75VStandard average current diode rating : 1A, 2A, 3A, 4A, 5AStandard peak current diode rating: 5A,10A, 15ATransformer: 200mA, 250mA, 500mA, 750mA, 1A, 2A, 5A

It is given Eripplepk-pk= 0.75V Standard average current diode rating : 1A, 2A, 3A, 4A, 5A…

Answered: VIBO HaO Deg V vrdg = 24Vdo RL 120 Ohm…

Engineering

Electrical Engineering

VIBO HaO Deg V vrdg = 24Vdo RL 120 Ohm c2

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)

10th Edition

ISBN:9781337399128

Author:Russell E. Smith

Publisher:Russell E. Smith

Chapter12: Electronic Control Devices

Section: Chapter Questions

Problem 4RQ: What is the difference between a diode and rectifier?

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Question

Industrial Electronics

Please give the step-by-step solution of the following:
(a) Standard average current diode rating

(b) Standard peak current diode rating

2. Design a power supply by specifying their rating to the nearest standard values.
220 VIBO H0 Deg
Vrdg = 24Vdc
RL
120 Ohm
Eripplepk-pk = 0.75V
Standard average current diode rating : 1A, 2A, 3A, 4A, 5A
Standard peak current diode rating: 5A,10A, 15A
Transformer: 200mA, 250mA, 500mA, 750mA, 1A, 2A, 5A

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