Vhat is the équation for retention factor (Rf)? O 1) (distance traveled from the origin to the compound)/(distance traveled by th origin to the solvent front) O 2) (distance traveled from the bottom of the plate to the compound)/(distance 2) traveled from the bottom of the plate to the solvent front) 3) (distance traveled from the bottom of the plate to the solvent front)/(distance traveled from the bottom of the plate to the compound) 4) (distance traveled from the origin to the solvent front)/(distance traveled from the origin to the compound)

The liquid-liquid extraction technique takes advantage of the solubility difference of a given compound in two immiscible solvents. Group of answer choices True False

What mass of MgCl₂ 6H₂O is required to make a 0.200 dm³ stock solution containing 25.0 ppm Mg(II)? What volumes of this stock solution are required to make 10.0 cm³ standard solutions containing 5.00, 1.00 and 0.10 ppm Mg(II)?

Please answer all 5 questions (it could be short answers). 5-1. What is the main barrier to separating liquid mixtures of less than 500 mL by distillation? 5-2. A sample mixture of ethyl benzoate (bp 212 Celsius) and dodecane (bp 216.2 Celsius) is injected on two GC columns. Column A has DC710 silicone oil as the stationary phase, and column B uses polyethylene glycol as the stationary phase. Which substance would be certain to elute first from column A and would the same material be expected to elute first from column B? Which column, A or B, would be expected to give the better separation of these two substances? 5-3. Question 5-2 refers to separating a mixture of two high boiling liquids by gas chromatography. These materials have similar boiling points. List several GC variables and conditions that would make it easier to separate thesesubstances by gas chromatography 5-4. Capillary GC columns have better resolution than packed columns even though the enormous surface area…

+275 3 =117-33 = 29.33 4 c. CHALLENGE PROBLEM: Unfortunately, right before the trip you come down with a case of the Heebie-Geebies. Luckily your Nana has a sure-fire cure: she gives you an eyedropper bottle with the label: "Take 10 drops per 15 lb. body weight per dose four times a day until the geebies subside. Contains 8g heebie bark per 100 drops solution. 64 drops = 1 tsp." If you weigh 128 lbs. and the 4-oz bottle is just under half-full are you at risk of running out of granny's geebie-tonic before the end of the trip? Note: 3 teaspoons = 1 tablespoon and 2 tablespoons = 1 ounce. (HINT: begin your answer with the person's weight.) 28 012a-UsingNumbers.docx AD 012.4 1 Last printed 8/9/2022 12:38:00 PM

A 100% 7:06 PM Wed Jan 29 Unanswered •1 attempt left • Due on Jan 30 0.100 g sample is dissolved in 10.0 g of a solvent (Kf = 20.0 kg °C/mol), If the freezing point of the solution is found to be 1.22°C lower than the freezing point of pure solvent, the molecular weight of the sample is -g/mol. 328 0.610 164 244 1.64 Submit

Calculate the water hardness (mg L-1 of CaCO3)  (i.e. calculate the mass of CaCO3) please show working out. thank you :) Sample No. 1 2 3 4 Final Burette reading (mL)   24.40 46.90 24.70 47.20 Initial Burette reading (mL) 0.10 24.40 2.10 24.70 Final-Initial Titre (mL) 24.30 22.50 22.60 22.50