Verify Stokes' theorem for the helicoid (1, 0) = First, compute the surface integral: = (VF) Sff(r.)dr de, where a = 0 f(r,0)= b = pi/2 Finally, the value of the surface integral is (r cos 0, r sin 0, 0) where (r, 6) lies in the rectangle [0, 1] × [0, π/2], and F is the vector field F = (8z, 7x, 2y). ,c=0 ,d=1 , and (use "t" for theta). Next compute the line integral on that part of the boundary from (1,0,0) to (0, 1, π/2). SF dr=f9(6) do, where a=0 9(0) = b = , and (use "t" for theta).