Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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- For given BJT, B=200. The applied input frequency is 20 Mhz and net internal capacitance is 100 pF. What is the CE short circuit current gain at ẞ cut-off frequency?arrow_forwardIn normal-phase TLC, a compound with a Rf value of 0.7 is _______ polar than a compound with a Rf value of 0.4 a. More b. Lessarrow_forwardIf vsig is a triangle waveform, determine the maximum amplitude that vsig can have? Showyour calculation.arrow_forward
- Use the image below to help answers parts a and b.in an LRC type circuit series the inductive reactance is XL=484 ohms. and I=0.8 amps is the measured current amplitude.A) In the inductor determine the amplitude of the voltage.B)If the LRC circuit is at resonance frequency find the capacitive reactance.arrow_forwardThe parameters of the circuit shown in Figure 1 are: B = 100, VBE = 0.7 V, VT = 26 mV, Cbc =12 pF, Cce= 15 pF and Cbe = 44 pF. Based on the circuit: i) Determine the midband voltage gain, A, = Vo. vi ii) Calculate the low cut-off frequencies caused by C1 and C2. iii) Calculate CE if the cut-off caused by this capacitor is 88 Hz. iv) Based on values in (ii) and (iii), what is the dominant low cut-off frequency? v) Determine the high cut-off frequency. +18V 3.3k2 C2=0.022µF C,=0.1µF V, 20k2 15k2 Vo 1k2 CE 6802 2.73V Vsarrow_forwardFor given BJT, B=200. The applied input frequency is 20 Mhz and net internal capacitance is 100 pF. What is the CE short circuit current gain at ẞ cut-off frequency?arrow_forward
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