VB1 R1 ww 13 R5 R3 w VB2 ww R2 w R4 In the circuit above, the current through R5 (labeled as 13) is 15 mA. Given this information, find the magnitude of the current through the other resistors and the magnitude of the voltage drop across the second battery VB2. Note the WebWork units for current (I) are amp. For resistance, you can use ohm or kohm. VB1 = 3 volts 13 = 15 mA R1 = 380 R2 = 5000 R3 = 4902 R4 = 4300 R5 = 1400 IRI " IR2 " IR3 IRA 9. VB2 = 9.
VB1 R1 ww 13 R5 R3 w VB2 ww R2 w R4 In the circuit above, the current through R5 (labeled as 13) is 15 mA. Given this information, find the magnitude of the current through the other resistors and the magnitude of the voltage drop across the second battery VB2. Note the WebWork units for current (I) are amp. For resistance, you can use ohm or kohm. VB1 = 3 volts 13 = 15 mA R1 = 380 R2 = 5000 R3 = 4902 R4 = 4300 R5 = 1400 IRI " IR2 " IR3 IRA 9. VB2 = 9.
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Transcribed Image Text:VB1
R1
ww
13 R5
R3
w
VB2
ww
R2
w
R4
In the circuit above, the current through R5 (labeled as 13) is 15 mA. Given this information, find the magnitude of the current through the other resistors and
the magnitude of the voltage drop across the second battery VB2.
Note the WebWork units for current (I) are amp. For resistance, you can use ohm or kohm.
VB1 = 3 volts
13 = 15 mA
R1 = 380
R2 = 5000
R3 = 4902
R4 = 4300
R5 = 1400
IRI
"
IR2
"
IR3
IRA
9.
VB2 =
9.
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