Vapor Compression Refrigeration System A refrigerating machine using R-12 as refrigerant operates between the pressures 2.5 bar and 9.0 bar. The compression is isentropic and there is not under cooling in the condenser. The vapour is dry and saturated condition at the beginning of the compression. Estimate the theoretical COP. If the actual COP is 0.65 of theoretical COP, calculate the net cooling produced per hour. The refrigerant flow is 5 Kg/min. The properties of refrigerant are : Pressure Satu. temp. (Bar) 9.0 Enthalpy (kJ/kg) Liquid 70.55 Entropy (kJ/kg K) Vapour (°C) Vapour 36 201.8 0.6836 2.5 -7 29.62 Take specific heat of superheated vapour at 9 bar as 0.64 kJ/kg K. 184.5 0.7001 Compressor pressure = 9 bar Evaporator pressure = 2.5 bar COND COND 2' 36°C 36°C COMP EVAPO EVAPO -7°C -7°C h4 Professor Dr. Mohammad Zoynal ABEDIN Dept. of ME, DUET, Gazipur MCE 4391 Department of EEE IUT, Board Bazar, Gazipur Basic Mechanical Engineering EXPN COMP 2.

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Entropy

In physics, entropy means the amount of disorder or the degree of randomness associated with a thermodynamic system. The system is not self-organized when the entropy of the system is high. For instance, when a system is at an elevated temperature, its molecules are in random motion, vibrating and colliding with each other. During this scenario, the probability of finding a molecule at a particular place twice, is low. Under this circumstance, the system can be said to be in a high entropy.