values of X, the number of components in a system submitted for repair that must be replaced, are 1, 2, 3, and 4 with onding probabilities 0.15, 0.15, 0.35, and 0.35, respectively. alculate E(X) and then E(5 – X). E(X) = 5 - X) - 150 ould the repair facility be better off charging a flat fee of $95 or else the amount $ [(5 – X) Wote: It is not generally true that 150 e repair facility | -Select--- v be better off charging a flat fee of $95 because E (5 - X)]
values of X, the number of components in a system submitted for repair that must be replaced, are 1, 2, 3, and 4 with onding probabilities 0.15, 0.15, 0.35, and 0.35, respectively. alculate E(X) and then E(5 – X). E(X) = 5 - X) - 150 ould the repair facility be better off charging a flat fee of $95 or else the amount $ [(5 – X) Wote: It is not generally true that 150 e repair facility | -Select--- v be better off charging a flat fee of $95 because E (5 - X)]
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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E(X) = ∑X(p)
E( c - x ) = c - E(x)
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