values of X, the number of components in a system submitted for repair that must be replaced, are 1, 2, 3, and 4 with onding probabilities 0.15, 0.15, 0.35, and 0.35, respectively. alculate E(X) and then E(5 – X). E(X) = 5 - X) - 150 ould the repair facility be better off charging a flat fee of $95 or else the amount $ [(5 – X) Wote: It is not generally true that 150 e repair facility | -Select--- v be better off charging a flat fee of $95 because E (5 - X)]

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Question
Possible values of X, the number of components in a system submitted for repair that must be replaced, are 1, 2, 3, and 4 with
corresponding probabilities 0.15, 0.15, 0.35, and 0.35, respectively.
(a) Calculate E(X) and then E(5 – X).
E(X)
=
E(5 - X)
(b) Would the repair facility be better off charging a flat fee of $95 or else the amount $
150
?
[(5 - X)]
Note: It is not generally true that E.
E(Y)
150
The repair facility
-Select--- v be better off charging a flat fee of $95 because E
(5 - X)
Transcribed Image Text:Possible values of X, the number of components in a system submitted for repair that must be replaced, are 1, 2, 3, and 4 with corresponding probabilities 0.15, 0.15, 0.35, and 0.35, respectively. (a) Calculate E(X) and then E(5 – X). E(X) = E(5 - X) (b) Would the repair facility be better off charging a flat fee of $95 or else the amount $ 150 ? [(5 - X)] Note: It is not generally true that E. E(Y) 150 The repair facility -Select--- v be better off charging a flat fee of $95 because E (5 - X)
Expert Solution
Step 1

We have given that 

E(X) = ∑X(p)

E( c - x ) = c - E(x) 

 

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