V=445 suced by 2070: Q5/ A circular curve of 145.00 m radius is to be set out between two straights having deflection angle of 30°right, and 30 chainage of the point of intersection as 5 + 40.00. Calculate the necessary data for setting out the curve taking the length of one chain as 10 m. bl (10 H

V=445 suced by 2070: Q5/ A circular curve of 145.00 m radius is to be set out between two straights having deflection angle of 30°right, and 30 chainage of the point of intersection as 5 + 40.00. Calculate the necessary data for setting out the curve taking the length of one chain as 10 m. bl (10 H

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

PROBLEM 1: The distance from the middle of the curve to the point of intersection of tangent of a circular curve is 19.65 m. If the radius of the curve is 400 m. Compute the middle ordinate.a. 18.73 m c. 169.37 mb. 36.35 m d. 73.20 m
The long chord from the P.C to the P.T of a compound curve is 293.77 meters long and the angles its makes with the longer and shorter tangents are 13.94⁰ and 20.32° respectively. If the common tangent is parallel to the long chord, find the stationing of P.T. if the stationing of P.C. is 10 + 233.55. WRITE YOUR ANSWERS in meters. (For example, the stationing is 10+ 252.3 --> write this as 10252.3)
هل من امكانيل هو قن عيريف B Q2: Is it possible to fit a horizontal curve (D=4 degree) at point (B) together with another Horizontal curve (D=3 degree) at point (C) as shown the figure. Knowing that the lengths of AB, BC and CD are 140, 230 and 250m respectively? If the length of BC is increased to 750m determine the station of point (D), if the station (A) is (100+00)? 45° 30 B. Lois DEll
A compound curve has the following data: I, = 28°,I, = 31°,D, = 3°, and D, = 4°. Find the stationing of PCc. Use Sta PI = 30 + 120.5. %3D a. 30 + 110.73 b. 30 + 118.46 C. 30 + 114.88 d. 30 + 106.97
The length of the curve of a simple curve having a degree of curve 4o is equal to 210 m. Compute the area of the fillet of the curve. Choices: 1442.69 m2 1244.69 m2 1224.69 m2 1424.69 m2
In the figure shown AB = 103.20m with A at station 10 + 158.93. The angle VAC is 15°21’ and angle VBC is 18°31’, where C is the point to which a simple curve is to be constructed tangent to the line AB. (Use four decimal places) a) Determine the radius of the curve b) Determine the stationing of point C. c) Determine the stationing of P.T
H.M 6: Use the following figure, to calculate the curve elevation of full and main stations by using Analytic method? P.V.I -3% P.Y.T P.V.C 36. Som 41 +60 =240m 十

The tangent thru the point P.C. has a direction due north and the tangent through P.T. has a bearing of N50°E. It has a radius of 200m. Using Arc basis. Station of P.C. is 9+200.COmpute the following:A. Tangent distance of the curveB. Long Chord of the curveC. Stationing at P.T.
PROBLEM 48: The distance from the midpoint of the curve to the point of intersection of the tangent of a simple curve is 40 m. If radius is 220 m, determine the length of curve. a. 247.31 m b. 132.66 m c. 123.66 m d. 163.26 m
Example 1.3. Two tangents intersect at chainage 59 + 6(1. the ieflection angle hrng 50° 30'. Całculate the necessary data for setting out a curve of 15 chains radius ta vonnect the two tangents if it is intended to set out the curve by offets from vkords. Take peg interval equal to 100 links, length of the chain heing equai to 20 metres (i00 links). Example 1.4. Calculate the necessary data for setting out the curve of example 1.3 if it is intended to set out the curve by Rankine's method of tangential angles. If the theodolite has a least count of 20", tabulate the actual readings of deflection angles to be set out. 3.
4. A curve formed by a Back Tangent with a bearing of N 30° W and a Forward Tangent with a bearing of N 85° E, has a degree of 15° defined by 100 feet of arc. The station of the point of intersection is 135+76. a. Calculate the station of PC. b. Calculate the station of PT. c. Calculate the longest distance between the long chord and the curve. d. Calculate shortest distance between the point of intersection and the curve.
Two straights AB and BC meet in an accessible point B and are to be connected by a simple curve of 600 m radius. Two points P and Q were selected on AB and BC respectively, and the following data were obtained: angle APQ = 150 degrees, angle CQP = 130 degrees, PQ = 125 m. If station of P is at 1+600 and using a 30 m full station, solve the following:-Station A -Station C -I -Deflection angle at Sta. 1+220 -Chord lenth at Sta. 1+250