V = pxr4 8 nxl A) If the volume of a liquid (V) flowing out per second of a pipe of length 1 and radius ris written by a student as: where p is the pressure difference between the two ends of the pipe and n is the coefficient of viscosity of the liquid having the dimensional formula [ML¹T-1]. Check if the equation of volume is dimensionally correct or not. Hint: n has the dimensional formula of [ML¯¹T¯¹].

Physics for Scientists and Engineers: Foundations and Connections
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ISBN:9781133939146
Author:Katz, Debora M.
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Activity 1:
A) If the volume of a liquid (V) flowing out per second of a pipe of length 1 and radius ris written by a student as:
pxr4
V =
8 xl'
, where p is the pressure difference between the two ends of the pipe and n is the coefficient of
viscosity of the liquid having the dimensional formula [ML-¹T-¹]. Check if the equation of volume is
dimensionally correct or not. Hint: n has the dimensional formula of [ML-¹T-¹].
B) Find the dimension for [B] and [y] that makes the following formula dimensionally correct:
Y
x²
(Knowing that t = time, F = force, v = velocity, x = distance).
t²
= Fv+
Transcribed Image Text:Activity 1: A) If the volume of a liquid (V) flowing out per second of a pipe of length 1 and radius ris written by a student as: pxr4 V = 8 xl' , where p is the pressure difference between the two ends of the pipe and n is the coefficient of viscosity of the liquid having the dimensional formula [ML-¹T-¹]. Check if the equation of volume is dimensionally correct or not. Hint: n has the dimensional formula of [ML-¹T-¹]. B) Find the dimension for [B] and [y] that makes the following formula dimensionally correct: Y x² (Knowing that t = time, F = force, v = velocity, x = distance). t² = Fv+
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