College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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The graph in the figure shows the velocity of a motorcycle police officer plotted as a function of time.

a. Find the instantaneous acceleration at t = 3, t = 7, and t = 11.

b. How far does the officer go in the first 5 s, first 9 s, and first 13 s?

v (m/s)
50
45
40
35
30
25
20
15
10
5
0
2 4 6 8 10 12 14
t(s)
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Transcribed Image Text:v (m/s) 50 45 40 35 30 25 20 15 10 5 0 2 4 6 8 10 12 14 t(s)
Expert Solution
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Step 1

In this question the velocity time graph is showing the velocity of a motorcycle police officer  

In part A we have to Find the instantaneous acceleration at t = 3, t = 7, and t = 11. 

The slope of velocity time graph shows accerlation 

For t = 3 sec

At t=3s, the graph is horizontal, slope is 0, so the acceleration is 0.  

For t= 7 sec 

From t=5s to t=9s, the acceleration is constant (from the graph) and equal to 

45-20/9-5 = 6.25 m/s2 

For t= 11 sec 

From t=9s to t=13s, the acceleration is constant and equal to 0-45/13-9 = -11.25 m/s2

 

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