The graph in the figure shows the velocity of a motorcycle police officer plotted as a function of time.
a. Find the instantaneous acceleration at t = 3, t = 7, and t = 11.
b. How far does the officer go in the first 5 s, first 9 s, and first 13 s?
In this question the velocity time graph is showing the velocity of a motorcycle police officer
In part A we have to Find the instantaneous acceleration at t = 3, t = 7, and t = 11.
The slope of velocity time graph shows accerlation
For t = 3 sec
At t=3s, the graph is horizontal, slope is 0, so the acceleration is 0.
For t= 7 sec
From t=5s to t=9s, the acceleration is constant (from the graph) and equal to
45-20/9-5 = 6.25 m/s2
For t= 11 sec
From t=9s to t=13s, the acceleration is constant and equal to 0-45/13-9 = -11.25 m/s2
Step by step
Solved in 3 steps
