Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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- First pic the question Second pic i did not understand step 3arrow_forward٩arrow_forwardA step-down converter with RL load is operated at the switching frequency f= 2 Khz and a duty cycle k = 0.6. With V, 100 V, R = 50, L 5 mH, E-20 V. . I and I are respectively the minimum and the maximum instantaneous load current. The Boundary Conditions equations are: O a 1₂-he-2 + 16(1-2); I₁=Ize 3-4(1-e-3) b. 1₂ Ie 3+16(1-3); I₁=I₂e 2-4(1-e-02) Oc 1₂ = 1₁e03; I₁=I₂e02-4(1-e02) O d. 1₂=he 3+16(1-3); I₁=Ie +4(1-e-03)arrow_forward
- . In the transformer shown in the below figure, the inductance measured across the terminal 1 and 2 was 4 H with open terminals 3 and 4. It was 3 H when the terminal 3 and 4 were short circuited. The circuited. The coefficient of coupling would be 12 TV₁ Lp 20- M #33 L₁=2H ↑ V₂ 04arrow_forwardApplication: Construct the circuit in figure. R= 2,2KN, L = 1 mH, and C= 10 nF. L Necesssary Formulae: 1 Xc 2.π.f.C X.-2. π.f. L By using the formulea perform the calculations of Xc and XL then fill the table. f (Hz) Xc XL 50000 60000 70000 80000 90000 100000 110000 120000 130000 140000arrow_forwardFor the circuit in Figure: 1) Set up the equation for the upper supermesh. Response format: Ai1 ± Bi2 ± Ci3 ± Di4 = E 2) Set up the auxiliary equation for the top supermesh. Response format: Ai1 ± Bi2 ± Ci3 ± Di4 = E 3) Set up the equation for the lower supermesh. Response format: Ai1 ± Bi2 ± Ci3 ± Di4 = E 4) Set up the auxiliary equation for the lower supermesh. Response format: Ai1 ± Bi2 ± Ci3 ± Di4 = E 5) What is the value of ix in A?arrow_forward
- i need the answer quicklyarrow_forward. In the transformer shown in the below figure, the inductance measured across the terminal 1 and 2 was 4 H with open terminals 3 and 4. It was 3 H when the terminal 3 and 4 were short circuited. The circuited. The coefficient of coupling would be 12 TV₁ Lp 20- M #33 L₁=2H ↑ V₂ 04arrow_forwardFor the machine given in the figure has state diagram as 2-1 MUX X1 Y. CLK Select A A%3D0 A=0 A 0 A=1 A=1 (A) (B) Q=1 Q-0 Q=1 A=D0 A=0 A=1 A=1 A-0 A-0 (C) (D) Q=0 Q=1 A=1-arrow_forward
- Number of coil windings 300; slit width 12 mm How can I get the calibration factor by using ampere's law? Plz explain in detailarrow_forwardThe folkwing results were obtained on 220/440V transformer First Test:120W,12A, 30 V Second Test: 70 w, 3A, 225V Cakulate the circuit constants and show them on an approximate equivakent circut.arrow_forwardn 7 In step up transformer, secondary turns are less than primary turns. out of Select one: O True uestion O False VION MS team link Jump to... search Chparrow_forward
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