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V₁ = 100V RF = 2^ M I = SA R₁ = 6^ a) compute the back-emf (EG). b) compute the output power in Watts (W) and horsepower (hp). c) compute the torque in ft-lbf and N-m. d) neglecting all losses, compute the efficiency (n) if Pin is 400 W. EG n=1200rpm

V₁ = 100V RF = 2^ M I = SA R₁ = 6^ a) compute the back-emf (EG). b) compute the output power in Watts (W) and horsepower (hp). c) compute the torque in ft-lbf and N-m. d) neglecting all losses, compute the efficiency (n) if Pin is 400 W. EG n=1200rpm

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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For the following series motor

### Educational Content on Electric Circuits #### Diagram Explanation The diagram represents a simple electric motor circuit. Here's a detailed breakdown: - **Voltage Source (\( V_t \))**: The circuit is powered by a voltage source of 110 volts. - **Resistance (\( R_F \) and \( R_A \))**: The circuit includes a field resistance (\( R_F \)) of 2 ohms and an armature resistance (\( R_A \)) of 6 ohms. - **Current (\( I \))**: A current of 5 amperes flows through the circuit. - **Back EMF (\( E_g \))**: This is the electromotive force generated by the motor, denoted as \( E_g \). - **Motor Speed**: The motor operates at a speed of 1200 revolutions per minute (rpm). #### Problem Statements a) **Compute the Back-EMF (\( E_g \))**. b) **Compute the Output Power**: - In Watts (W) - In Horsepower (hp) c) **Compute the Torque**: - In foot-pounds-force (ft-lbf) - In Newton-meters (N-m) d) **Compute the Efficiency (\( \eta \))**: - Given that the input power (\( P_{\text{in}} \)) is 400 Watts, compute the efficiency, neglecting all losses. This educational content highlights fundamental concepts of electric circuits, particularly focusing on calculating back electromotive force, output power, torque, and efficiency of a motor. These computations are essential for understanding and designing efficient electric motors.
Transcribed Image Text:### Educational Content on Electric Circuits #### Diagram Explanation The diagram represents a simple electric motor circuit. Here's a detailed breakdown: - **Voltage Source (\( V_t \))**: The circuit is powered by a voltage source of 110 volts. - **Resistance (\( R_F \) and \( R_A \))**: The circuit includes a field resistance (\( R_F \)) of 2 ohms and an armature resistance (\( R_A \)) of 6 ohms. - **Current (\( I \))**: A current of 5 amperes flows through the circuit. - **Back EMF (\( E_g \))**: This is the electromotive force generated by the motor, denoted as \( E_g \). - **Motor Speed**: The motor operates at a speed of 1200 revolutions per minute (rpm). #### Problem Statements a) **Compute the Back-EMF (\( E_g \))**. b) **Compute the Output Power**: - In Watts (W) - In Horsepower (hp) c) **Compute the Torque**: - In foot-pounds-force (ft-lbf) - In Newton-meters (N-m) d) **Compute the Efficiency (\( \eta \))**: - Given that the input power (\( P_{\text{in}} \)) is 400 Watts, compute the efficiency, neglecting all losses. This educational content highlights fundamental concepts of electric circuits, particularly focusing on calculating back electromotive force, output power, torque, and efficiency of a motor. These computations are essential for understanding and designing efficient electric motors.
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