Using transit rule, adjust the closed traverse.Compute also the linear error of closure and the relative precision. Lines Bearings Due north N 45° E S 60° E S 20° W S 86º59' w Distance(m) 400 1 to 2 2 to 3 3 to 4 800 700 4 to 5 5 to 1 600 966.34 Compute the area of the adjusted traverse in number 1 using DMD.

Using transit rule, adjust the closed traverse.Compute also the linear error of closure and the relative precision. Lines Bearings Due north N 45° E S 60° E S 20° W S 86º59' w Distance(m) 400 1 to 2 2 to 3 3 to 4 800 700 4 to 5 5 to 1 600 966.34 Compute the area of the adjusted traverse in number 1 using DMD.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Q3: A: Draw the diagram of traverse classification. B: In closed traverse ABCD. The partial coordinates were known as shown below. Determine its area by DMD method. 04 N Dofland OWODY dienstl it with (nm) dinostim Mem. AB BC CD DA ΔΧ 40 -80 -50 AY 60 100 -70
Q7) Calculate the coordinates. Check whether the error is acceptable. Make corrections. N 59.0701g S2 145.5558g S1 161.51849 A x=315.122m $3 S6 120.6210g 167.8089g S4 F S5 Y (m) x (m) Дх B (grad) a (grad) S (m) Ay STATION A 137.619 214.077 170.542 D 189.664 225.219 F 156.907 A 8 y=74.056m
Problem 3 The following are the observed bearings of a close traverse. Compute the error of interior angle, and compute the bearing of each line. Assume line "DE" is the best line. Draw the traverse. CORRECTED BEARINGS LINE AB BC CD DE EF FA LENGTH 99 m 48 146 119 43 ≈57 OBSERVED BEARINGS FORWARD S 81°33' E S 42°13' E S 30°48' W N 35°55' W N 45°33' E N 28°11' W BACKWARD N 80°18' W N 43°20' W N 31°03' E S 35°55' E S 45°40' W S 27°25' E FORWARD BACKWARD
QUESTION 1 (a) Line F/S B/S 236°50' AB 53°30' BC 165°20' 344°00' CD 116°30' 294°20' DE 236°30' 58°40' EA 303⁰50¹ 123°50' In the above traverse remove the errors introduced by local attraction and calculate the angular misclose. Distribute the angular error and recompute adjusted bearings for the figure. Accept datum line EA.
PROBLEM 1. Given in the accompanying tabulation are the adjusted latitude and adjusted departure of a closed traverse. Calculate the area by the DMD method LINE ADJ ADJ LAT DEP AB - 125.055 + 196.387 BC +20.241 + 241.003 CD +180.107 + 65.326 DE +210.169 - 104.519 EF -74.003 - 260.516 FA - 211.459 - 137.681
3456 7 8910 200 b00 Find Po FiL assume i 8/
FG 217.73 m S 20°30' E N 21°00' W 4. The following are the observed lengths and magnetic bearings of a closed compass traverse. Adjust the observed directions of each line and tabulate values accordingly OBSERVED BEARING BACKWARD S 35°00' W S 56°45' E N 76°00' E N 42°15' E N 39°00' W N 85°30' W LINE LENGTH FORWARD AB BC CD DE EF FA 330.75m 305.43m 325.28 m 201.10 m 225.25m 375.55m N 34055' E N 56°30' W S 75°45' W S 42°15' W S 38 45' E S 85°15' E
Bearing Angle Traverse Given the tabulated measurement of the closed traverse as shown. Determine the area of the traverse using DPD Method. Line Length Bearing AB 413.600 m N 09°30’ W BC 304.380 m N 55°06’ W CD 407.210 m S 57°35’ W DE Unknown S 04°05’ E EA 649.630 m Unknown Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.
Using the data below, compute for the Linear Error of Closure Also, Determine the adjusted latitude and departure using compass rule: Line Distance Latitude Departure Adjustment (Lat) Adjustment (Dep) Adjusted Lat Adjusted Dep 1-2 388.08 -234.363 -309.322 2-3 732.72 732.665 8.952 3-4 324.78 -22.938 323.969 4-1 477.24 -476.557 -25.531 Express all answer unitless and with 3 decimals for A to J Next
Direction: Given the following data on the table. Fill up the needed data. Balance the traverse by transit rule. Solve the area by DPD or DMD. Sketch the traverse. All values must be in decimal places. COMPUTED ADJUSTED DEPARTURE LIN ADJUST ADJUST DISTAN СЕ (M) AZIMUT COMPUTED ADJUSTED LATITUDE ADJUST ED AZIMUT BEARIN DPD DOUBLE E G LATITUDE DEPARTURE ED DISTAN СЕ ED AREA (from S) BEARIN H (nearest (nearest minute) minute) +NL -SL +ED -WD +NL -SL +ED -WD АВ E S 70-29 N 10-00 650.00 ВС 895.00 CD S 26-28 315.00 DE S 65-33 W EA 875.00 410.00 N 45-31 W ТОTAL LEC : RP (nearest hundred) AREA ..
A. TACHEOMETRY 1. A transit is set up at a distance back of the zero end of a level base line 240 m. long. The base line being marked by stakes at every 30 m. A rod is then held at successive stations along the base line. The stadia intervals at each location of the rod are tabulated below. It is required to determine the stadia interval factor of the instrument. Distance Stadia Distance Stadia Intercept Intercept 30 0.297 150 1.482 60 0.591 180 1.776 90 0.885 210 2.073 120 1.188 240 2.367
PROBLEM: A closed traverse has the following observed quantities. Line Distance (m) Bearing S 80°46' W AB 550.43 BC 295.08 N 11°18' W S 72°28' E S 18°17' E S 80°30' W CD 610.19 DE 886.17 EF 456.57 FG GA 357.66 N 88°53' E Compute the bearing of line BC. Your answer Compute the length of line FG.