Using the pictures of the trials given, I need help answering this question. 1.From your knowledge of X and Y in the equation (as well as the rate in a given experiment from your graph) calculate k from your data. Rate= K[I^-]^x [S2O8^2-]^y

Based on the result from the room temperature experiment (20°C), estimate the time it would take a piece of zinc to completely react in hydrochloric acid at a temperature of 30°C. Remember, as a general rule the rate will double for every 10°C increase in temperature. **Note: the result from the experiment was that it took Zinc 2 minutes and 27 seconds to completely react in hydrochloric acid at room temperature (20°C) a) about 1:20 b) about 0:40 c) about 5:20 d) about 13:30

Using the data in the table, calculate the rate constant of Trial [A] (M) [B] (M) Rate (M/s) this reaction. 1 0.260 0.280 0.0119 A + B → C+ D 2 0.260 0.784 0.0933 3 0.312 0.280 0.0143 Units k = M-²s-1 M-'s-! M-s-!

- 1 Under certain conditions the rate of this reaction is zero order in ammonia with a rate constant of 0.0080 M's : 2 NH3 (g) → N, (g)+3 H, (g) Suppose a 5.0 L flask is charged under these conditions with 300. mmol of ammonia. How much is left 2.0 s later? You may assume no other reaction is important. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits. x10 ?

Consider the reaction 5Br (aq) + BrO, (aq) + 6H+ (aq)→3B12 (aq) + 3H20(1) The average rate of consumption of Br is 1.36x104 M/s over the first two minutes. What is the average rate of formation of Br2 during the same time interval? Express your answer with the appropriate units. • View Available Hint(s) HẢ |] ? Rate of formation of Br2 Value Units %3D

- 1 Under certain conditions the rate of this reaction is zero order in hydrogen iodide with a rate constant of 0.0045 M's : 2 HI (g) → H, (g)+I, (g) Suppose a 250. mL flask is charged under these conditions with 350. mmol of hydrogen iodide. How much is left 80. s later? You may assume no other reaction is important. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits. x10

The rate of a certain reaction was studied at various temperatures. The table shows temperature (7) and rate constant (k) data collected during the experiments. Plot the data to answer the questions. What is the value of the activation energy, Ea, for this reaction? E₁ = 122.7 What is the value of the pre-exponential factor (sometimes called the frequency factor), A, for this reaction? A= 1.147 X10¹2 kJ mol-1 Incorrect T(K) 400 420 440 460 480 500 520 540 560 580 k (s-¹) 0.000108 0.000626 0.00310 0.0134 0.0511 0.175 0.547 1.57 4.18 10.4

Use the provided initial rate data to derive the rate law for the reaction whose equation is: OCI (aq) + (aq) → OI¯¯(aq) + Cl¯¯(aq) Trial [OCI-] (mol/L) 1 0.0040 2 0.0020 3 0.0020 [I-] (mol/L) Initial rate (mol/L sec) 0.0020 0.00300 0.0040 0.00450 0.0020 0.00675 Determine the rate law expression and the value of the rate constant k with appropriate units for this reaction.

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Help with the question on the right Question 23 Identify the rate-determining step based on the rate law you found in question 23. Given these data for the acid-catalyzed reaction in question 22, find the rate law. 0–H (RCOOH), M [R'OHJ, M (HAJ, M Initial Rate, M-min"' - R-C+ k2 R С—0—Н + HA A- 0.35 0.35 0.50 4.60 0.50 0.62 0.35 0.35 8.14 0.81 0.50 10.6 0.35 0.50 0.75 0–H 9.84 Group 1 0–H 0–H k3 Rate = k[RCOOH][R'OH] R-Ć+ A- R 0–H R—С—0—Н + Rate = k[RCOOH][R'OH][HA] k4 0–H R-ó+ A- Group 2 Rate = k[RCOOR']/{[RCOOH][R'OH]} H Rate = k[R'OH] 0–H Rate = k[RCOOH] k5 R- C-0–R' R-C-0–H + H,о + НА R-o+ A- Group 3 Step 2 or Step 3 O Step 1 or Step 2 Step 1 Step 3 Step 2 Step 1