Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN: 9780134463216
Author: Robert F. Blitzer
Publisher: PEARSON
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### Problem Statement

Using the method from class, determine the inverse \( f^{-1}(x) \) of \( f(x) = \frac{\sqrt[3]{x} + 5}{2} \).

\[ f^{-1}(x) = \boxed{\phantom{f^{-1}(x)}} \]

### Explanation

This exercise requires finding the inverse function of \( f(x) = \frac{\sqrt[3]{x} + 5}{2} \). The method involves swapping the variables \( x \) and \( y \) in the function and solving for \( y \).

**Steps to Find the Inverse:**

1. Write the original function replacing \( f(x) \) with \( y \):
   \[ y = \frac{\sqrt[3]{x} + 5}{2} \]

2. Swap \( x \) and \( y \):
   \[ x = \frac{\sqrt[3]{y} + 5}{2} \]

3. Solve for \( y \) to find the inverse:
   - Multiply both sides by 2:
     \[ 2x = \sqrt[3]{y} + 5 \]
   - Subtract 5 from both sides:
     \[ 2x - 5 = \sqrt[3]{y} \]
   - Cube both sides to solve for \( y \):
     \[ y = (2x - 5)^3 \]

Thus, the inverse function is:
\[ f^{-1}(x) = (2x - 5)^3 \]

### Final Answer

\[ f^{-1}(x) = (2x - 5)^3 \]
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Transcribed Image Text:### Problem Statement Using the method from class, determine the inverse \( f^{-1}(x) \) of \( f(x) = \frac{\sqrt[3]{x} + 5}{2} \). \[ f^{-1}(x) = \boxed{\phantom{f^{-1}(x)}} \] ### Explanation This exercise requires finding the inverse function of \( f(x) = \frac{\sqrt[3]{x} + 5}{2} \). The method involves swapping the variables \( x \) and \( y \) in the function and solving for \( y \). **Steps to Find the Inverse:** 1. Write the original function replacing \( f(x) \) with \( y \): \[ y = \frac{\sqrt[3]{x} + 5}{2} \] 2. Swap \( x \) and \( y \): \[ x = \frac{\sqrt[3]{y} + 5}{2} \] 3. Solve for \( y \) to find the inverse: - Multiply both sides by 2: \[ 2x = \sqrt[3]{y} + 5 \] - Subtract 5 from both sides: \[ 2x - 5 = \sqrt[3]{y} \] - Cube both sides to solve for \( y \): \[ y = (2x - 5)^3 \] Thus, the inverse function is: \[ f^{-1}(x) = (2x - 5)^3 \] ### Final Answer \[ f^{-1}(x) = (2x - 5)^3 \]
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