Using the laws of boolean algebra simplify these expressions and list the laws used to justify each step. And show a truth table for the original expression and verify that your final expression satisfies the same truth table. DeMorgan and Consensus are not needed. The final result should have 4 products, where each product has at most 2 literals. a. ABC + ABC’ + A’C + A’B’C + AB’C b. A'B' + A'BC' + (A + C')' c. A' + A'B'CD' + A'B'C'D' + AB'C' + AB'CD' + ABD + BC'D
Using the laws of boolean algebra simplify these expressions and list the laws used to justify each step. And show a truth table for the original expression and verify that your final expression satisfies the same truth table. DeMorgan and Consensus are not needed. The final result should have 4 products, where each product has at most 2 literals.
a. ABC + ABC’ + A’C + A’B’C + AB’C
b. A'B' + A'BC' + (A + C')'
c. A' + A'B'CD' + A'B'C'D' + AB'C' + AB'CD' + ABD + BC'D
We are given the expression a) ABC + ABC’ + A’C + A’B’C + AB’C b)A'B' + A'BC' + (A + C')' c) A' + A'B'CD' + A'B'C'D' + AB'C' + AB'CD' + ABD + BC'D Our objective is to simplify it using the laws of Boolean algebra without the use of DeMorgan and Consensus.
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