Using the following equation and your result from Step 30, determine % concentration (mass percent) of acetic acid (CH3COOH) in the vinegar and record it in Data Table 2. Note: The density of vinegar is 1.00 g/ml and the molecular mass of CH3COOH is 60.05 g/mol. % CH3COOH=mol CH3COOH1 L vinegar×1 L1000 mL×1 mL vinegar1.006 g vinegar×60.05 g CH3COOH1 mol CH3COOH×100%
Using the following equation and your result from Step 30, determine % concentration (mass percent) of acetic acid (CH3COOH) in the vinegar and record it in Data Table 2. Note: The density of vinegar is 1.00 g/ml and the molecular mass of CH3COOH is 60.05 g/mol. % CH3COOH=mol CH3COOH1 L vinegar×1 L1000 mL×1 mL vinegar1.006 g vinegar×60.05 g CH3COOH1 mol CH3COOH×100%
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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- Using the following equation and your result from Step 30, determine % concentration (mass percent) of acetic acid (CH3COOH) in the vinegar and record it in Data Table 2.
Note: The density of vinegar is 1.00 g/ml and the molecular mass of CH3COOH is 60.05 g/mol.
% CH3COOH=mol CH3COOH1 L vinegar×1 L1000 mL×1 mL vinegar1.006 g vinegar×60.05 g CH3COOH1 mol CH3COOH×100%
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