Using the compass (Bowditch) rule, adjust the departures and latitudes of the traverse given in the table below. The coordinates of station A are X=18300.00 ft and Y=17500.00 ft. Course Length AB 202.74 283.87 498.37 320.33 380.78 BC CD DE EA Departures Latitudes -127.565 -157.577 151.42 -240.113 481.592 -125.5 -379.946 -25.193 0.063 =1686.09 0.001 128.224 294.722 Calculate the x-coordinates for the other stations. Express your answers in feet to seven significant figures separated by commas. | ΑΣΦ | it vec| B.C.D.E18172.43, 18323.85, 18805.44,18679.94,18300.001 ft Submit Previous Answers Bequest Answer Part B ? Calculate the y-coordinates for the other stations. Express your answers in feet to seven significant figures separated by commas. 195] ΑΣΦ. 11 Ivec ? B.C.D. E= 17342.423,17102.31,17230.53,17525.26,17500.06 ft

Using the compass (Bowditch) rule, adjust the departures and latitudes of the traverse given in the table below. The coordinates of station A are X=18300.00 ft and Y=17500.00 ft. Course Length AB 202.74 283.87 498.37 320.33 380.78 BC CD DE EA Departures Latitudes -127.565 -157.577 151.42 -240.113 481.592 -125.5 -379.946 -25.193 0.063 =1686.09 0.001 128.224 294.722 Calculate the x-coordinates for the other stations. Express your answers in feet to seven significant figures separated by commas. | ΑΣΦ | it vec| B.C.D.E18172.43, 18323.85, 18805.44,18679.94,18300.001 ft Submit Previous Answers Bequest Answer Part B ? Calculate the y-coordinates for the other stations. Express your answers in feet to seven significant figures separated by commas. 195] ΑΣΦ. 11 Ivec ? B.C.D. E= 17342.423,17102.31,17230.53,17525.26,17500.06 ft

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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AzMk1 A B C D E AzMk2 Latitude +210.73 +288.33 +169.95 +278.94 Departure -148.14 +63.23 -51.85 +122.72 Y Coordinate 3,476.12 3,864.22 4,812.33 5,091.22 In this open traverse, what is the error in the latitudes? X Coordinate 3,133.23 3,212.33 3,198.32 3,093.41
Glven the following notes for a closed traverse. Determine the following a) Coordinates of station E (xy). (Blank 1.Blank 2) b) Area of the traversed using coordinate method in m^2. Blank 3 ADJUSTED ADJUSTED LINE DEPARTURE LATITUDE АВ 395.60 352.00 ВС 591.60 23.40 CD 78.30 -558.20 DE -746.30 -102.50 EA -319.20 285.30 Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer
The following are the incorrected consecutive coordinated of a traverse. Adjust the traverse by Third Rule elaboratively for each line and in the form of table as well? Length (ft) Line Consecutive Coordinates Latitude Departure АВ 70 +21.500 -65.450 BC 80 -80.755 -5.250 CD 43 -41.000 +13.550 DE 38 -14.250 +35.150 EA 115 +114.150 +22.315
: Determine the graph and conversion of the following angles.1. Convert the following azimuth 190º15.40'45” to heading.2. Graphic 66º7´9”3. Convert the following heading S 74º9'30” W to azimuth.4. Convert the following azimuth 200º46´7.12” to heading.5. Graph 245º52´14”
PROBLEM 1. Given in the accompanying tabulation are the adjusted latitude and adjusted departure of a closed traverse. Calculate the area by the DMD method LINE ADJ ADJ LAT DEP AB - 125.055 + 196.387 BC +20.241 + 241.003 CD +180.107 + 65.326 DE +210.169 - 104.519 EF -74.003 - 260.516 FA - 211.459 - 137.681
I. Determine the interior angles of each stations and azimuths for each surveying lines. AZAB = INTZA = 40 40P 37 AZBC = INTZB = C 30 22 AZCD = INTZC = 66° 40' AZDE = INTZD = 15° 12 1s° 58 AZEA = INTZE =
A closed traverse was surveyed and the resulting values of latitudes and departures were computed. Determine the correct bearing of line CD using compass rule. LINE BEARING DISTANCE LATITUDE DEPARTURE А-В N 77 38' E 907.00 + 194.25 885.95 В-С S 46 20' W 249.00 - 171.92 180.12 C-D S 10 43' E 348.00 - 341.93 + 64.71 D-E S 84 43' W 523.00 - 48.16 520.78 E-A N 37 01' W 444.80 + 355.16 267.79
Situation 4] From the given data of a closed traverse, The adjusted bearing of BC using compass rule. The adjusted bearing of DA using compass rule. The total area using Coordinates method. The total area using Double Parallel Distance method. i. ii. iii. iv. Distance, m 368.76 Line Bearing N15°18'E AB BC CD S85046'E S18030W N77035W 645.38 467.86 DA 593.00
Fill in the blanks: (Use compass rule) Azimuth Corrected Corrected Corrected Departure Line Length Bearing Departure Latitude North Latitude Length AB 89.31 45°10' ВС 219.76 151.18 72°05' CD 161052' 228 43' 300°42' DE 159.10 EA 232.26 Determine the perimeter of the Corrected Closed Traverse.
Use DMD & DPD Method to calculate the Area of the closed traverse whose data is given below. Draw the figure. LINE CORRECTED DEPARTURE CORRECTED DISTANCE 413.53341 596.41168 AB CORRECTED LATITUDE +296.42872 - 246.85339 + 104.50281 154.07815 + 288.33990 BC CD +542.92753 - 597.93576 - 233.33167 606.99919 DA 279.61356
Q5) If |BC| = 166.176 m, determine Azimuth (AB), JAB| and coordinates of point C x=906.54m B x=879.94m A y388.09m 115.91g y=253.95m
Situation 4] From the given data ofa dosed traverse, The adjusted bearing of BC using compassrule. The adjusted bearing of DA using compass rule. The total area using Coordinates method. The total area using Double Parallel Distance method. i. ii. i. iv. Distance, m 368.76 Bearing N15°18'E S85046'E S18°30W N77035W Line АВ ВС 645.38 CD 467.86 DA 593.00