Using the above information determine the following Test Results         Differenece Sample Difference Standard Error T-Stat P-Value

Class Mean Standard Deviation N Lower 12.11 2.83 122 Working 13.01 2.91 541 Middle 14.99 2.93 475 Upper 15.44 2.83 34 As our confidence in the result increases, how does the size of the confidence interval change?

Constructing a Confidence Interval for a Population Proportion In a survey funded by a large university, 750 of 1000 adult Seattle residents said they did not believe they could contract a sexually transmitted infection (STI). Construct a 95% confidence interval for the proportion of all adult Seattle residents who don't believe they can contract an STI. Select the correct interval below. O (.728, .772) O (.723, .777) O (.718, .782) O (.713, .878) O (.665, .835)

You are interested in finding a 95% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 13 randomly selected college students. Round answers to 3 decimal places where possible.   4 11 11 7 10 7 9 2 8 11 9 4 12   a. To compute the confidence interval use a     distribution. b. With 95% confidence the population mean number of days of class that college students miss is between  and   days. c. If many groups of 13 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About  percent of these confidence intervals will contain the true population mean number of missed class days and about  percent will not contain the true population mean number of missed class days.

Temperatures The table on the next page gives theaverage high temperatures in January and July for severalEuropean cities. Write a 90% confidence interval for themean temperature difference between summer and winterin Europe. Be sure to check conditions for inference, andclearly explain what your interval means. Mean HighTemperatures 1°F2City Jan. JulyVienna 34 75Copenhagen 36 72Paris 42 76Berlin 35 74Athens 54 90Rome 54 88Amsterdam 40 69Madrid 47 87London 44 73Edinburgh 43 65Moscow 21 76Belgrade 37 84

You are interested in finding a 99% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 15 randomly selected college students. Round answers to 3 decimal places where possible.   1 7 12 10 2 0 9 0 7 11 6 11 10 2 12 b. With 99% confidence the population mean number of days of class that college students miss is between   ?  and   ?   days. c. If many groups of 15 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About   ?  percent of these confidence intervals will contain the true population mean number of missed class days and about   ?   percent will not contain the true population mean number of missed class days.

Proper explanation and final conclusion don't use plagiarism word and chat gpt Part a,b,c

You are interested in finding a 98% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 14 randomly selected college students. Round answers to 3 decimal places where possible.   12 5 7 4 6 9 11 11 9 8 5 9 10 11   a. To compute the confidence interval use a     distribution. b. With 98% confidence the population mean number of days of class that college students miss is between  and   days. c. If many groups of 14 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About  percent of these confidence intervals will contain the true population mean number of missed class days and about  percent will not contain the true population mean number of missed

You are interested in finding a 90% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 15 randomly selected college students. Round answers to 3 decimal places where possible.   6 9 10 7 6 5 1 9 2 3 2 1 2 8 6   a. To compute the confidence interval use a     distribution. b. With 90% confidence the population mean number of days of class that college students miss is between  and   days. c. If many groups of 15 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About  percent of these confidence intervals will contain the true population mean number of missed class days and about  percent will not contain the true population mean number of missed class days.