Using superposition, determine the current through the 802 resistor for the network below E₁ = 10 V 20° + E₂ = 4V 180'with E2 shorted = 180" with E1 shorted = 180= R₁ Xc www 26Ω HE HI 5202 2 XL m 4 Ω R₂ * 8 Ω units units units
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- The picture shows three LC circuits, two of them with capacitors of capacitance C and the three with coils of inductance L, the three circuits are coupled by means of two capacitors Cc capacitors.L inductance coils, the three circuits are coupled by means of two capacitors of capacitance Cc. The currentscirculating through each mesh are those indicated in the figure: I1, I2 and I3. Using Kirchhoff's law for voltagesand taking into account the definition of current I = -dQ/dt, find the system of coupled equations for the systemand then find the angular normal frequencies of the system.Ministry of Manpower Directorate General of Technological Education Salalah College of Technology Zlectrical Inginearina Problem - 8 Refer to the circuit below and -25V C2 N. compute the following: i) Total capacitance ii) Voltage across C, iii)Charge across C, iv)Voltage across C5 5 uF C1 5 uF 5 uF C4 5 uF C6 5 uF -16-65V. C5 5 uF (Take V, as 25V) 8-35V VT 25Vfor the circuit shown below If v_in=5 sin2m10t then corner frequency will be ......Hz 1 UF 2 k Ohm 1 k Ohim 050 060 070 080 vin
- H.W 2 An AC circuit includes two sections AB and BC in series. The section AB consists of two branches in parallel. The first of these is formed of resistance of 60 2 in series with a capacitor of 50 mF, while the second consists of a resistance of 60 2 having an inductance of 250 mH. The section BC consists of a resistance of 100 N having an inductance of 300 mH. The frequency of the current is 50 Hz. The voltage across section AB is 500 V. What is the voltage across the section BC?sohw circuit diagram and step by step solution plsExeras: 1. Be rebistance of a sm length of oire is cön sr. Detia) the resitance of an8m longth of the same wire, b) the ength of the seme wine when the res tfonce is 4W s. 2. A Piece f re of crss-cfisndd area 2 muy go0 sr. Finid the rebutance of a wie of the some length and maferial if the crss secfional area s SMm. b). the crosss so area of the wire of the some length ond maeriol of resisfance soD2 3. A oril cons o turns of oopperwirehaving a cm-seton area of 0.8 mmn, The maan Lengtb perfurn is s0 čm anithe nosiãfivity of Cu s 0.02 um. Finh the resistonca of the coil ond pwer absorbed 4. An aluminum wire 7.5m. Lang is consacfed parallel writha copper 201ire de m larg. uhen a curent of rdix passd throngh the Cmibination, iř in fannl tht the curent the aluminung wire ik 3Aup The diamefer of the alumsinum wire is 1,0 mm. Defermane the diamefer of the copper wire. has rebi tance of by the cril when camecfed acm8 110V&c supply?
- Please show your detailed solution Number 14 The current in a series inductive circuit is 7.5 A at 25 Hz. The circuit takes 425 W, and the power factor is 0.47. The resistance of the circuit is A. 7.32 ohms C. 7.98 ohms B. 7.86 ohms D. 7.56 ohmsUnit 19 Elec Princ LO2 2022 2023.pdf - Work - Microsoft Edge https://moodle.nptcgroup.ac.uk/pluginfile.php/1421751/mod_resource/conte.. !!!! a) I=9.3 /0° A4 mim f = 350 Hz Find: 24 22 b) Z1 Vi HH 11.1 µF E E + V 5 of 7 i) The values of V1 and V2. ii) The value of the supply voltage and its phase angle. iii) Draw the circuit phasor diagram. (Z3) 31 Q2 V2 0.93 mH (For each section provide your answers in both polar and cartesian form.) Ơ X QSolve the power triangle at Z6 using the following network law below.1.) Kirchorff's LawGiven:V1, V2, and V3 = 220∠0° V, 50 HzZ1 = 7+j8 ohmsZ2 = 6+j3 ohmsZ3 = 5+j5 ohmsZ4 = 2+j3 ohmsZ5 = 8+j4 ohmsZ6 = 1+j9 ohms
- Determine the mesh currents I1 and I2 in phasor formQS: For the coupled circuit shown in Figure 3, find the voltage across the capacitor of -j102 reactance with Vr-1020 V and V-10290 V? j20 jsa jsa Figure 3The dioces are ideal. write the Fransfer Characteidie equati ons ( &, as a funchiar g &) Plot &o agaiwet &, imdicaling all intrcepts, slopes and Volt ope lerels. Sketch bo f bq =40 sin wt. Indicate al voltage lezels - %3D 1OK lok lov