Using mesh currents analysis technique finds the current i1 and iz of the circuit described in fig. 3.0.1 H5 AF100 cos(1000r)100 20,1 H4=414.12-45* A12=1120 A4,(1)=1414Cos(10001-45) mA12()=1000Cos(10001) mA4-1.4142-45" mA12=120 mANone of the above

Given frequency of the circuit ω=1000 rad/sec. Convert inductor and capacitor into impedance form…

Using mesh currents analysis technique finds the current i and i2 of the circuit described in fig. 3. 0.1 H 5 AF 100 cos(1000r) 100 2 0.1 H 40) 4=414.12-45 A 12=1120 A 14,(1)=1414Cos(10001-45) mA 1,0 1000Cos(10001) mA 4-1.4142-45 mA

Using mesh currents analysis technique finds the current i and i2 of the circuit described in fig. 3. 0.1 H 5 AF 100 cos(1000r) 100 2 0.1 H 40) 4=414.12-45 A 12=1120 A 14,(1)=1414Cos(10001-45) mA 1,0 1000Cos(10001) mA 4-1.4142-45 mA

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

100%

Using mesh currents analysis technique finds the current i1 and iz of the circuit described in fig. 3.
0.1 H
5 AF
100 cos(1000r)
100 2
0,1 H
4=414.12-45* A
12=1120 A
4,(1)=1414Cos(10001-45) mA
12()=1000Cos(10001) mA
4-1.4142-45" mA
12=120 mA
None of the above

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