using Karnaugh map to simple this truth table and write Boolean expression Irputs Dutput 0. 0. 0. N OD- IDOS 10011 OOD1 e oo0 ODDD 1117 AAAE

Design a code converter that converts a decimal digit from BCD to excess-3 code, the input variables are organized as (A BC D) respectively with A is the MSB, the output variables are organized as (W X Y Z) respectively with W is the MSB, put the invalid decimal numbers as don't care. X= BCD'+B'D+B'C X= BC'D'+B'D+BC X= BC'D'+B'D+B'C X= BC'D'+BD+B'C

| Solve all parts. Will give thumb's up| If you can't do all please don't attempt the questions.

USE DIGITAL LOGIC AND DESIGN Part 1: In Figure_4; we have 4-bit Comparator using 2-bit Comparators block. You have to satisfy given condition by applying all data on figure 4. At the end, given condition should produce HIGH output and other two should be LOW.   A3 A2 A1 A0 = 1101 and B3 B2 B1 B0 = 1110                                                                            Figure_4   Part 2: The serial data-input waveform (Data in) and data-select inputs (S0 and S1) are shown in Figure_5. Determine the data-output waveforms from D0 through D3.                                                                            Figure_5   Part 3: Decoder can be useful when we have to decode some specific numbers from their equivalent code. Figure 6 has a concept of 3 to 8 line decoder from which you have to generate output waveform from D0 to D7 with proper relationship to input.                                                                      Figure_6   Part 4: The data-input and…

Q1/The binary number ( 1011011011011.1110111001101)= ( ) in octal number *

Simplify the following Boolean expressions using Karnaugh Map and draw the logic circuits. f = wxyz + wxyz + wxyż + wxỹz + wxyz + wxyz + wxỹz + wãyz

A logic function is expressed by the equation = 0.1.8.9.4. Plot the the values on the K-map below Note: w is the msb (most significant bit) 3 x 10 0- - W X 1 00 01 Write the simplified Sum of Products (SOP) expression. Use yz WIM or "" for NOT; 11 10 for AND; "+" for OR (without the quotation marks.

5. Assume d3d₂d₁do is a BCD number and derive Boolean expression for segments b,c,e,f,g in a seven segment display in terms of d3d₂d₁do g 4 d Based on your boolean expressions derive the values of b,c,e,f,g segments when i. d3d₂d₁do= (0100) 2 ii. d3d₂d₁do = (0111)₂ iii. d3d2d₁do (1000)2

9. The initial value of AX is 01011100, what will be the value of AX after the instruction NOT AX? a.10100011 b. 10100110 c. 010100011 d. NOTC

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