Using a .01 level of significance, determine whether these samples of women and men have significantly different levels of safety knowledge Men      Women    4              7    6              5    7              6    3              7 What is the null and alternative hypothesis  what is the critical region what is the test statistic Reject null hypothesis? what can be concluded

Test the claim that the proportion of people who own cats is smaller than 70% at the 0.05 significance level. Based on a sample of 100 people, 69% owned catsThe test statistic is: ? (to 2 decimals)The p-value is: ?  (to 2 decimals)

* Compare the absolute difference between conditions (e.g. the mean was 2.5 words higher for condition B) * Explain what the mean, median, or mode tells us about the data.  * What does the measure of variance tell us about the data in each condition? How do these two conditions compare?

Responses to a survey question are broken down according to employment status and the sample results are given below. At the 0.10 significance level, test the claim that response and employment status are independent. Round your answer to 3 decimal places. Employment status   Yes No Undecided Employed 30 15 5 Unemployed 20 25 10   Group of answer choices p-value=0.051, evidence not support claim p-value=0.051, evidence support claim p-value=0.513, evidence support claim p-value=0.513, evidence not support claim p-value=0.130, evidence not support claim

need test statistic and p value thank you

Do Predicted Temperatures match Actual Temperatures? The table shows the predicted and actual temperatures for a seven day period. Assume that the two samples are randomly selected. At the 0.1 significance level, test the claim that there is no mean difference in the predicted and actual temperatures.(Be sure to subtract in the same direction). Predicted Temperatures ⁰F Actual Temperatures ⁰F Difference ⁰F 81 76   75 79   86 83   85 90   82 82   77 78   78 80   What are the correct hypotheses? (Select the correct symbols and values.)H0: Select an answer p μ₁ s₁² μ(d) σ₁² x̄₂ μ x̄₁  ? < = > ≥ ≠ ≤  Select an answer s₁² μ 0 σ₁² μ₂ μ₁ x̄₁ p x̄₂ H1: Select an answer μ₂ x̄₁ x̄₂ p μ s₂² μ₁ μ(d) σ₂²  ? ≤ ≠ > ≥ < =  Select an answer μ₂ x̄₂ μ 0 σ₁² x̄₁ μ₁ p s₁²     Original Claim = Select an answer H₁ H₀ df =  Based on the hypotheses, find the following: Test Statistic =  (Round to three decimal places.)Critical value(s) = ±± (Round to three decimal…

Can you write it in text please so I can copy and paste it!! Thank you

Given the data below, what is the calculated test statistic?   Placebo Medication 1 Medication 2 3 4 9 1 3 7 3 5 8 2 5 11 4 4 9 3     SS1 = 5.33 SS2 = 2.8 SS3 = 8.8 T1 = 16 T2 = 21 T3 = 44 n1 = 6 n2 = 5 n3 = 5     ∑X2 = 53 Do you reject the null?      Yes     No   Was there a treatment effect for type of medication on number of anti-anxiety symptoms?     Yes     No

Q: Using the data (provided below this question) apply ANOVA to determine if the mean response for value for the dollar is the same for different types of cell phones. Use a 5% significance level if the problem doesn’t give an alpha. Note: Please only provide the t stat, p-value, and critical value, no need to explain the whole process. Gender Carrier Type Usage Signal strength Value for the Dollar Customer Service M AT&T Smart High 5 4 4 M AT&T Smart High 5 4 2 M AT&T Smart Average 4 4 4 M AT&T Smart Very high 2 3 3 M AT&T Smart Very high 5 5 2 M AT&T Smart Very high 4 3 5 M AT&T Smart Very high 3 4 4 F AT&T Smart Very high 3 2 3 F AT&T Smart Very high 4 3 4 M AT&T Smart Very high 3 3 1 M Other Smart Average 1 2 4 M Sprint Smart Very high 3 5 4 M Sprint Smart Very high 3 5 3 F Sprint Smart Average 2 5 4 F Sprint Smart Average 3 5 4 M Verizon Smart Average 4 3 3 F Verizon Smart Very high 4 3 2 M Verizon…

Test the claim that the proportion of people who own cats is larger than 40% at the 0.1 significance level.   Based on a sample of 500 people, 46% owned catsThe test statistic is:  (to 2 decimals)The p-value is:  (to 2 decimals)