Use z scores to compare the given values. Based on sample data, newbom males have weights with a mean of 3287.6 g and a standard deviation of 563.8 g. Newbom females have weights with a mean of 3008.2 g and a standard deviation of 680.6 g. Who has the weight that is more extreme relative to the group from which they came: a male who weighs 1700 g or a female who weighs 1700 g? Since the z score for the male is z = and the z score for the female is z, the (Round to two decimal places.) " has the weight that is more extreme.

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Use z scores to compare the given values.
Based on sample data, newborn males have weights with a mean of 3287.6 g and a standard deviation of 563.8 g. Newborn females have weights with a mean of 3008.2 g and a standard deviation of 680.6 g. Who has the weight that is more extreme relative to the group from which they came: a male who weighs 1700 g or a
female who weighs 1700 g?
Since the z score for the male is z =
and the z score for the female is z =
the
V has the weight that is more extreme.
(Round to two decimal places.)
Transcribed Image Text:Use z scores to compare the given values. Based on sample data, newborn males have weights with a mean of 3287.6 g and a standard deviation of 563.8 g. Newborn females have weights with a mean of 3008.2 g and a standard deviation of 680.6 g. Who has the weight that is more extreme relative to the group from which they came: a male who weighs 1700 g or a female who weighs 1700 g? Since the z score for the male is z = and the z score for the female is z = the V has the weight that is more extreme. (Round to two decimal places.)
Expert Solution
Step 1

Consider that the mean and standard deviation of a random variable x are and s, respectively.

Thus, the z-score of that random variable x is z = (x)/s.

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