Use the worked example above to help you solve this problem. Four capacitors are connected in series with a battery, as in the figure below, where C₁ = 3.30 pF, C₂ = 6.44 µF, C3 = 12.2 μF, C₁ = 25.0 µF, V = 18.3 V. C₁ C₂ G C (a) Calculate the capacitance of the equivalent capacitor. 0.580 x Did you accidentally divide or take the inverse in your calculation? µF (b) Compute the charge on C3- 10.614 x Your response differs from the correct answer by more than 10%. Double check your calculations. HC (c) Find the voltage drop across C3- 0.87 X Your response differs from the correct answer by more than 10%. Double check your calculations. V

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Use the worked example above to help you solve this problem. Four capacitors are connected in series
with a battery, as in the figure below, where C₁ = 3.30 μF, C₂ = 6.44 μF, C3= 12.2 µF, C4 = 25.0 μF,
V = 18.3 V.
C₁
C₂
C3
CA
(a) Calculate the capacitance of the equivalent capacitor.
0.580
X
Did you accidentally divide or take the inverse in your calculation? µF
(b) Compute the charge on C3.
10.614
x
Your response differs from the correct answer by more than 10%. Double check your calculations.
μC
(c) Find the voltage drop across C3-
0.87
x
Your response differs from the correct answer by more than 10%. Double check your calculations.
V
Use the values from PRACTICE IT to help you work this exercise. C is removed from the circuit, leaving
only three capacitors in series.
(a) Find the equivalent capacitance.
Ceq = 0.540
X
You are on the right track, but you have made an algebraic mistake. Checking the units might help
you find where you went wrong. μF
(b) Find the charge on C₂-
Q = 9.882
X
You are correct, QCV, but your value of C was incorrect. μC
(c) Find the voltage drop across C₂-
AV 1.534
X
What factors affect the potential difference across a capacitor? How do the voltages across a series
set of capacitors relate to the total voltage across the series? V
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Transcribed Image Text:Use the worked example above to help you solve this problem. Four capacitors are connected in series with a battery, as in the figure below, where C₁ = 3.30 μF, C₂ = 6.44 μF, C3= 12.2 µF, C4 = 25.0 μF, V = 18.3 V. C₁ C₂ C3 CA (a) Calculate the capacitance of the equivalent capacitor. 0.580 X Did you accidentally divide or take the inverse in your calculation? µF (b) Compute the charge on C3. 10.614 x Your response differs from the correct answer by more than 10%. Double check your calculations. μC (c) Find the voltage drop across C3- 0.87 x Your response differs from the correct answer by more than 10%. Double check your calculations. V Use the values from PRACTICE IT to help you work this exercise. C is removed from the circuit, leaving only three capacitors in series. (a) Find the equivalent capacitance. Ceq = 0.540 X You are on the right track, but you have made an algebraic mistake. Checking the units might help you find where you went wrong. μF (b) Find the charge on C₂- Q = 9.882 X You are correct, QCV, but your value of C was incorrect. μC (c) Find the voltage drop across C₂- AV 1.534 X What factors affect the potential difference across a capacitor? How do the voltages across a series set of capacitors relate to the total voltage across the series? V Need Help? Read It
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