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Use the van der Waals equation of state to calculate the pressure of 4.00 mol of SO, at 453K in a 3.80 L vessel. Van der Waals constants can be found in the van der Waals constants table. P = atm Use the ideal gas equation to cakulate the pressure under the same conditions. P= 39.15 atm

Use the van der Waals equation of state to calculate the pressure of 4.00 mol of SO, at 453K in a 3.80 L vessel. Van der Waals constants can be found in the van der Waals constants table. P = atm Use the ideal gas equation to cakulate the pressure under the same conditions. P= 39.15 atm

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter5: The Gaseous State
Section: Chapter Questions
Problem 5.28QP
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8:21 >4OB 00 • 83% i 00 Use the van der Waals equation of state to calculate the pressure of 4.00 mol of SO, at 453K in a 3.80 L vessel. Van der Waals constants can be found in the van der Waals constants table. Use the ideal gas equation to cakulate the pressure under the same conditions. P = 39.15 atm In a 16.80 L vessel, the pressure of 4.00 mol of SO, at 453 K is 8.85 atm when calculated using the ideal gas equation and 8.59 atm when calculated using the van der Waals equation of state. II
Transcribed Image Text:8:21 >4OB 00 • 83% i 00 Use the van der Waals equation of state to calculate the pressure of 4.00 mol of SO, at 453K in a 3.80 L vessel. Van der Waals constants can be found in the van der Waals constants table. Use the ideal gas equation to cakulate the pressure under the same conditions. P = 39.15 atm In a 16.80 L vessel, the pressure of 4.00 mol of SO, at 453 K is 8.85 atm when calculated using the ideal gas equation and 8.59 atm when calculated using the van der Waals equation of state. II
8:22 >10 000 • 83% i 00 In a 16.80 L vessel, the pressure of 4.00 mol of SO, at 453 K is 8.85 atm when calkulated using the ideal gas equation and 8.59 atm when calculated using the van der Waals equation of state. Why is the percent difference in the pressures calculated using the two different equations greater when the gas is in the 3.80 L vessel compared to the 16.80L vessel? O The attractive forces between molecules become less ofa factor at the hisher pressure in the 3,80L vessel. O The molecular volume is a smaller part of the total volume of the 3.8OL vessel. O The molecular volume is a larger part of the total volume of the 3.80L vessel. O The attractive forces between molecules become a greater factor at the higher pressure in the 3.80 L vessel. II
Transcribed Image Text:8:22 >10 000 • 83% i 00 In a 16.80 L vessel, the pressure of 4.00 mol of SO, at 453 K is 8.85 atm when calkulated using the ideal gas equation and 8.59 atm when calculated using the van der Waals equation of state. Why is the percent difference in the pressures calculated using the two different equations greater when the gas is in the 3.80 L vessel compared to the 16.80L vessel? O The attractive forces between molecules become less ofa factor at the hisher pressure in the 3,80L vessel. O The molecular volume is a smaller part of the total volume of the 3.8OL vessel. O The molecular volume is a larger part of the total volume of the 3.80L vessel. O The attractive forces between molecules become a greater factor at the higher pressure in the 3.80 L vessel. II
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