Use the standard normal table to determine the following probabilities: P(-1.04 < Z < 2.05) = 0.8306 P(Z < - 1.04 or Z> 2.05) = 0.1694

Calculate the mean value (expected value) of the following discrete variable x: x-0, 1, 2, 3, 4, 5, 6 %3D p(x) 3D 0.2, 0.2, , 0.05 0.15,0.15, 0.15, 0.1

Let X = {Email, In Person, Instant Message, Text Message}; P(Email) = 0.06 P(In Person) = 0.55 P(Instant Message) = 0.24 P(Text Message) = 0.15   Is this model a probability distribution? A. Yes. B. No. C. Maybe.

A random sample of n = 100 observations is selected from a population with u = 31 and o = 21. Approximate the probabilities shown below. a. P(x2 28) c. P(xs 28.2) b. P(22.1sxs26.8) d. P(x2 27.0) Click the icon to view the table of normal curve areas.

Dr. Wilson is considering investing a fixed sum of money in each of three business ventures. Assume that the probability distribution for the number of successful ventures out of three is as follows:                                   X                            P(X)                      0                               .022                     1                               .194                    2                                .434                    3                                .350   What is the expected value for the number of successful ventures? What is the standard deviation for the number of successful ventures? What is the probability that Dr. Wilson will enjoy at least two successful ventures? What is the probability that Dr. Wilson will enjoy no successful ventures?

In a binomial distribution, n=8 and pie=0.36. Find the probabilities of the following events. a. X=5 b. X<=5 c. X>=6

Supposed Y follow a binomial distribution with n = 15 and p = 0.4. a.) Find the exact probabilities of Y < 8 and Y = 8 (from the included tables). b.) Compare these to the corresponding values found by using the normal approximation (from the included tables).

The mean height of women in a country​ (ages 20−​29) is 64.1 inches. A random sample of 75 women in this age group is selected. What is the probability that the mean height for the sample is greater than 65 ​inches? Assume σ=2.58. The probability that the mean height for the sample is greater than 65 inches is

Suppose a life insurance company sells a $160,000 1-year term life insurance policy to a 20-year-old female for $330. According to the National Vital Statistics Report, 58(21), the probability that th female survives the year is 0.999544. Compute and interpret the expected value of this policy to the insurance company. The expected value is $. (Round to the nearest cent as needed.). Which of the following interpretations of the expected value is correct? Select the correct choice below and fill in the answer box to complete your choice. (Round to the nearest cent as needed.) OA. The insurance company expects to make a profit of $ OB. The insurance company expects to make a maximum profit of $ OC. The insurance company expects to make a minimum profit of $ OD. The insurance company expects to make a profit of $ ! 1 Q @ 2 W 3 E $ 4 R on every 20-year-old female it insures for 1 year. on every 20-year-old female it insures for 1 year. on every 20-year-old female it insures for 1 month. on…

About 40% of all US adults will try to inflate an insurance claim to cover the deductible. Suppose that you work at an insurance company and just received 128 insurance claims. You are interested in the number of inflated claims. Is it fair to say this represents a binomial setting? Explain. Would it be reasonable to use the normal approximation? Explain. What is the probability that more than 80 of the claims are inflated?