Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why Interpret the results In a random sample of 45 people, the mean body mass index (BMI) was 26.9 and the standard deviation was 6.06. Which distribution should be used to construct the confidence interval? Choose the correct answer below. O A. Use a t-distribution because the sample is random, the population is normal, and o is unknown O B. Use a t-distribution because the sample is random, n2 30, and o is unknown. O C. Use a normal distribution because the sample is random, n2 30, and o is known. O D. Use a normal distribution because the sample is random, the population is normal, and o is known. O E. Neither a normal distribution nor a t-distribution can be used because either the sample is not random, or n<30, and the population is not known to be normal Select the correct choice below and, if necessary, fil in any answer boxes to complete your choice. O A. The 99% confidence interval is ( ) (Round to two decimal places as needed.) O B. Neither distribution can be used to construct the confidence interval. Interpret the results. Choose the correct answer below. O A. If a large sample of people are taken approximately 99% of them will have a BMI between the bounds of the confidence interval Ne Textbook Calculator 935 12/5/2 60F 99+ O Type here to search

You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 60 home theater systems has a mean price of $110.00. Assume the population standard deviation is $17.20. Construct a 90% confidence interval for the population mean. The 90% confidence interval is ( (Round to two decimal places as needed.)

Construct the confidence interval for the population mean.

You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 38 business​ days, the mean closing price of a certain stock was ​$119.97. Assume the population standard deviation is ​$10.88.

You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals.   A random sample of 40 home theater systems has a mean price of ​$117.00.Assume the population standard deviation is $18.40.

You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of $114.00. Assume the population standard deviation is $15.10. Construct a 90% confidence interval for the population mean. The 90% confidence interval is (\,\ (Round to two decimal places as needed.)

Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a random sample of 46 people, the mean body mass index (BMI) was 29.5 and the standard deviation was 6.16 Which distribution should be used to construct the confidence interval? Choose the correct answer below. A. Use a t-distribution because the sample is random, n2 30, and a is unknown. O B. Use a normal distribution because the sample is random, the population is normal, and a is known. OC. Use a t-distribution because the sample is random, the population is normal, and o is unknown. OD. Use a normal distribution because the sample is random, na 30, and o is known. O E. Neither a normal distribution nor a t-distribution can be used because either the sample is not random, or n< 30, and the population is not known to be normal. Select the correct choice below and,…

Use the standard normal distribution or the t-distribution to construct a 95% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a random sample of 45 people, the mean body mass index (BMI) was 27.4 and the standard deviation was 6.13. Which distribution should be used to construct the confidence interval? Choose the correct answer below. O A. Use a t-distribution because the sample is random, the population is normal, and a is unknown. O B. Use a normal distribution because the sample is random, the population is normal, and o is known. c. Use a t-distribution because the sample is random, n2 30, and o is unknown. XD. Use a normal distribution because the sample is random, n2 30, and a is known. OE. Neither a normal distribution nor a t-distribution can be used because either the sample is not random, or n< 30, and the population is not known to be normal. Select the correct choice below and,…

You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 40 home theater systems has a mean price of $130.00. Assume the population standard deviation is $18.50. The 90% confidence interval is ( 125.19), 134.81). (Round to two decimal places as needed.) Construct a 95% confidence interval for the population mean. The 95% confidence interval is ( 124.27 , 135.73). (Round to two decimal places as needed.) Interpret the results. Choose the correct answer below. O A. With 90% confidence, it can be said that the population mean price lies in the first interval. With 95% confidence, it can be said that the population mean price lies in the second interval. The 95% confidence interval is narrower than the 90%. O B. With 90%…

A random sample of 64 shoppers showed that they spend an average of $27.31 per visit at the Sunday Mornings Bookstore. The standard deviation of the population is $2.14. Find the 90% confidence interval of the true mean. Please include all work showing how you found your answer.