Cc.80. please do bothhbUse the References to access important values if needed for thisquestion.The activation energy for the gas phase decompositionof t-butyl propionate is 164 kJ.C,HCOOC(CH3)3 → (CH3)2C=CH2 + C₂H5 COOH-3The rate constant at 543 K is 1.09 x 10-³ s-¹. The rateconstant will be 0.0160 s¹ atK.Submit AnswerRetry Entire Group9 more group attempts remaining‒‒‒‒‒question.The activation energy for the gas phase decompositionof t-butyl alcohol is 274 kJ.-------(CH3)3 COH(CH3)2C=CH2 + H₂OThe rate constant at 809 K is 9.74 x 10-4s¹. The rateconstant will bes-1 at 855 K.Submit Answer9 more group attempts remainingRetry Entire Group

Use the References to access important values if needed for this question. The activation energy for the gas phase decomposition of t-butyl propionate is 164 kJ. C₂H5COOC(CH3)3 → (CH3)2C=CH2+ C₂H5 COOH The rate constant at 543 K is 1.09 x 10-3 s¹. The rate constant will be 0.0160 s¹ at K. Submit Answer 9 more group attempts remaining Retry Entire Group

Use the References to access important values if needed for this question. The activation energy for the gas phase decomposition of t-butyl propionate is 164 kJ. C₂H5COOC(CH3)3 → (CH3)2C=CH2+ C₂H5 COOH The rate constant at 543 K is 1.09 x 10-3 s¹. The rate constant will be 0.0160 s¹ at K. Submit Answer 9 more group attempts remaining Retry Entire Group

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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