**Current Attempt in Progress**Use the normal distribution to find a confidence interval for a proportion $ p $ given the relevant sample results. Give the best point estimate for $ p $, the margin of error, and the confidence interval. Assume the results come from a random sample.A 95% confidence interval for $ p $ given that $ \hat{p} = 0.41 $ and $ n = 450 $.Round your answer for the best point estimate to two decimal places, and your answers for the margin of error and the confidence interval to three decimal places.- Best point estimate = [input box]- Margin of error = ± [input box]- The 95% confidence interval is [input box] to [input box][Button: eTextbook and Media] [Button: Hint][Text: Save for Later] [Text: Attempts: 0 of 3 used] [Button: Submit Answer][Text: 62°F Cloudy]

Answered: Use the normal distribution to find a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 90% confidence interval for p given that p = 0.37 and n = 450. Round your answer for the best point estimate to two decimal places, and your answers for the margin of error and the confidence interval to three decimal places. Best point estimate = i Margin of error The 90% confidence interval is i ! to i
Assume that the population has a normal distribution. use a 95% Confidence level. In a survey of 3005 adults aged 57 through 85 years, it was found that 82% of them use at least one prescription medication. 1. How many people use at least one prescription medication. 2. Find the margin of error E that corresponds to a 95% confidence level. 3. Find the 95% confidence interval estimate of the population proportion p. 4. How many people must be surveyed if we want a confidence level of 99% and a margin of error of four percentage points? Use the sample proportion is 82%.
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 95% confidence interval for the proportion who will answer "Yes" to a question, given that 67 answered yes in a random sample of 85 people. Round your answers to three decimal places. Point estimate = i Margin of error = ± i The 95% confidence interval is i to
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 90% confidence interval for p given that p = 0.9 and n 130. Round your answer for the point estimate to two decimal places, and your answers for the margin of error and the confidence interval to three decimal places. Point estimate = Margin of error = ± i The 90% confidence interval is i to i
Use the normal distribution to find a confidence interval for a difference in proportions p1 – P2 given the relevant sample results. Assume the results come from random samples. A 99% confidence interval for p, – P2 given counts of 19 yes out of 200 sampled for Group 1 and 32 yes out 130 sampled for Group 2 Give the best estimate for p, – p2, the margin of error, and the confidence interval. Round your answers to three decimal places. Best estimate : Margin of error: i Confidence interval : i to i
Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence interval of (4.2,5.4) when estimating the mean height (in centimeters) of a sample of seedlings. The estimated margin of error is The sample mean is Search 6 17 + & 87 lyn 8 9 DYWAN DDI 8 0 0 0
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 99% confidence interval for p given that p = 0.33 and n = 550. Round your answer for the best point estimate to two decimal places, and your answers for the margin of error and the confidence interval to three decimal places.
K You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 35 home theater systems has a mean price of $131.00. Assume the population standard deviation is $15.50. Construct a 90% confidence interval for the population mean. The 90% confidence interval is (). (Round to two decimal places as needed.) W
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please round the answer to thousandth place. the other person did hundredths so It was incorrect

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