Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 99% confidence interval for the proportion of the population in Category A given that 21% of a sample of 400 are in Category A. Round your answer for the point estimate to two decimal places, and your answers for the margin of error and the confidence interval to three decimal places. Point estimate = . Margin of error =±. The 99% confidence interval is to .

A random survey of 200 pregnant women in New York City conducted by Epstein andRogers indicated that 150 of them preferred a female obstetrician to a male obstetrician.a. Find a point estimate for p, the proportion of all pregnant women in New York Citywho prefer a female obstetrician.__________ b. Find a 99% confidence interval for the proportion p of all pregnant women living inNew York City who prefer a female obstetrician.

Virginia wants to estimate the percentage of students who live more than three miles from the school. She wants to create a 95% confidence interval which has a margin of error of at most 5%. How many students should be polled to create the confidence interval? z0.10 z0.05 z0.025 z0.01 z0.005 1.282 1.645 1.960 2.326 2.576 Use the table of values above.

You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 42 business days, the mean closing price of a certain stock was $119.57. Assume the population standard deviation is $10.49. The 90% confidence interval is (. (Round to two decimal places as needed.) The 95% confidence interval is (Round to two decimal places as needed.) Which interval is wider? Choose the correct answer below. The 95% confidence interval The 90% confidence interval Interpret the results. A. You can be 90% confident that the population mean price of the stock is outside the bounds of the 90% confidence interval, and 95% confident for the 95% interval. B. You can be certain that the closing price of the stock was within the 90% confidence interval for approximately 38 of the 42 days, and was within the 95%…

You are given the smaple mean and the population m standard deviation. Use this info to construct the 90% and 95% confidence intervals for the population mean. Interpert the results and compare the widths of the confidence intervals. A random sample of 50 home theater systems has a mean price of $145. Assume the population standard deviation is $17.30

Tina catches a 14-pound bass.  She does not know the population mean or standard deviation.  So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds.  Find the t and calculate a 95% (α = .05) confidence interval.

In a survey, 28 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $45 and standard deviation of $14. Construct a confidence interval at a 99% confidence level. Give your answers to one decimal place. ________+________

You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals.   From a random sample of 65 ​dates, the mean record high daily temperature in a certain city has a mean of 84.70°F. Assume the population standard deviation is 14.54°F.

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When forming a confidence interval for matched-pair data the point estimate is the Select one: O A. standard deviation of the differences. OB. differences of the standard deviations. O C. mean of the differences. O D. difference of the means.