Use the node-voltage method to find v, in the circuit shown. 4.4 Answer: 24 V. 30 Ω 10 Ω 20 Ω +

4. Using the circuit below, compute the individual values of the voltage and the current using Kirchhoff's rules. 1+ +) => 3 V 1+ V2 9 V ww R3 6 Ω ww R1 2Ω ww R2 4 Ω

4.6 Use the node-voltage method to find vy in the circuit shown. 6 is 20 30 60 V v 24 0 303 Answer: 48 V. +.

For Wheatstone bridge circuit, the following values are given. Vsupply=120V; R₁ = 15 №; R₂ =3002; R3 = 30; R4 = 60; R5 = 300 • What is the voltage across R5? OV 45V 24 V 36 V Vsupply 2 m

Consider the circuit in Figure 4 to the left. We are interested in finding Vx using different analysis techniques. (a) Starting with Mesh analysis as shown in the figure to the right, find the mesh currents i1, i2, and i3 then determine Vx. Note that Vx = 4i2 1) -8.4 A, 1.2 A, -4 A, 4.8 V 2) -2 A, 1 A, -4 A, 4 V 3) -8.4 A, 0.1 A, -4 A, 0.4 V 4) -8.4 A, 0.6 A, -4 A, 2.4 V (b) . Another method is use superposition and adding the results algebraically. In this case, the value of  Vx due to the current source acting alone, and due to the voltage source acting alone is respectively equal to 1) -9.6 V, 12 V 2) -6 V, 24 V 3) 10.2 V, 12V 4) 2.4 V, 6 V

For Wheatstone bridge circuit, the following values are given. Vsupply=120V; R₁ = 15 2; R₂ =300; R3 = 30; R4 = 60; R5 = 300 • For the same condition, R₁ being disconnected, what will be the voltage across R5? 120 V 60 V 30 V OV Vsupply R₂ RO R₂