Use the method of variation of parameters to solve the initial value problem x = Ax + f(t). x(a)=x, using the following values. x(t) = A= 6-7 1-2 f(t)= 30 60 , x(0) = 0 0 -e¹+75 76¹-7est -e¹+est 7e-¹-est

Q: e the method of variation of parameters to solve the initial value problem x' = Ax + f(t), x(a) = x₂…

A: We have to find the value of x(t) with the method of the variation parameters.

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Q: y 1.510.500.511.-1.5-1-0.50 0.5 1 1.5 Identify the equation of the surface. ƒ(x, y) = y² + x f(x, y)…

A: AnswerGiven that:-Find out the equation of the surface?

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Q: 22. Let v₁ = (1, 6, 4), v₂ = (2, 4, -1), V3 = (-1, 2, 5), and W₁ = (1, -2,-5), w₂= (0, 8, 9). Use…

A: Given vectors are Here observed that So we have each of .In other words ,

Q: Use the method of variation of parameters to solve the initial value problem x' = Ax + f(t), x(a) =…

A: To solve the initial value problem x' = Ax + f(t), x(a) = x using the method of variation of…

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Q: Given a dataset D = {(x, y), i=1,2,..., m} consisting of m predictors x, = (₁, Fin) € R" and m…

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Q: Find and graph the image of D = {(x, y) = R² | 0 ≤ x ≤ 2, 1 ≤ y ≤ 4} under T(x, y) = (6x - 4y, 2x +…

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Q: What is wrong in this code that we get an error when it is run? >> clear all >> eq1=x*cos(x)^2 = 5…

A: Given:The code is,>> clear all>> eq1 = x*cos(x)^2 == 5>> solve(eq1,x)

Q: 7. 26-² s(s² + 4s +13)

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Q: Find a general solution to the given differential equation. y" - y' - 12y=0

A: We need to find a general solution to the given differential equation y''-y'-12y=0

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Q: 3. [Example 4.1.7 revisited] Let (bn)n≥1 be a sequence of real numbers such that lim bn = LE R.…

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Q: 5. 3 sin 2t

A: Given: Objective: To find the Laplace Transform.

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Q: I need help with this problem

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Q: h(x) = (x − 3)º(5x² + 3x)²

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Q: Use appropriate algebra and Theorem 7.2.1 to find the given inverse Laplace transform. (Write your…

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Q: for part b of the question, how did we get 2 answers after isolating for x?

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Q: SOLVE STEP BY STEP IN DIGITAL FORMAT Find the formula that describes a: {4,9,18,31,48,69,94,123}

A: 4,9,18,31,48,69,94,123So we have 491831486994123