Use the logarithmic Arrhenius equation and the following data showing the dependence of temperature and reaction rate constant k to predict the activation energy barrier (E₂) for the reaction shown. Hint: try graphing In(k) against 1/T from the data in the table and estimate the intercept, which is In(A), and the slope, which is Ea/R. In case you get stuck, you can use the Arrhenius factor for this reaction (A = 8.1 x 10⁹ mol-¹Ls-¹) and substitute it into the equation. 2NO2 (g) T(K) 673 683 693 703 713 O E = 1.2 x 105 kJmol-1 O E₂8.314 JK ¹mol-1 O E₂ -119601 Jmol-¹ O E₂ = 7.7 x 106 J O E₂ 1.2 x 10² kJmol-1 = 2NO (9) k (mol ¹Ls ¹) 7.8 10 14 18 24 + O2 (g)
Use the logarithmic Arrhenius equation and the following data showing the dependence of temperature and reaction rate constant k to predict the activation energy barrier (E₂) for the reaction shown. Hint: try graphing In(k) against 1/T from the data in the table and estimate the intercept, which is In(A), and the slope, which is Ea/R. In case you get stuck, you can use the Arrhenius factor for this reaction (A = 8.1 x 10⁹ mol-¹Ls-¹) and substitute it into the equation. 2NO2 (g) T(K) 673 683 693 703 713 O E = 1.2 x 105 kJmol-1 O E₂8.314 JK ¹mol-1 O E₂ -119601 Jmol-¹ O E₂ = 7.7 x 106 J O E₂ 1.2 x 10² kJmol-1 = 2NO (9) k (mol ¹Ls ¹) 7.8 10 14 18 24 + O2 (g)
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter11: Chemical Kinetics: Rates Of Reactions
Section: Chapter Questions
Problem 62QRT
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