
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
![**Using the Integral Test to Determine Series Convergence**
**Problem Statement:**
Use the Integral Test to determine if the following series converges. Be sure to prove that the Integral Test is valid for this series:
\[
\sum_{n=1}^{\infty} \frac{n}{(n^2+1)^2}
\]
**Explanation:**
The Integral Test can be used to determine the convergence of an infinite series. To apply the Integral Test, the function \( f(x) = \frac{x}{(x^2+1)^2} \) needs to be:
1. Positive
2. Continuous
3. Decreasing
on the interval \([1, \infty)\).
1. **Positivity:** The function is positive for \( x \geq 1 \).
2. **Continuity:** The function is continuous for all \( x \geq 1 \), since it's a rational function whose denominator does not equal zero in this interval.
3. **Decreasing Function Check:** To ensure the function is decreasing, compute the derivative \( f'(x) \) and evaluate whether it is negative for \( x \geq 1 \).
If these conditions are satisfied, compute the improper integral:
\[
\int_{1}^{\infty} \frac{x}{(x^2+1)^2} \, dx
\]
If the integral converges, so does the series. If the integral diverges, so does the series.](https://content.bartleby.com/qna-images/question/c1af4cad-3a82-431e-a6a5-54b2babd4110/63188370-9f70-4854-a167-3cedc9ccb711/xshx9w_thumbnail.jpeg)
Transcribed Image Text:**Using the Integral Test to Determine Series Convergence**
**Problem Statement:**
Use the Integral Test to determine if the following series converges. Be sure to prove that the Integral Test is valid for this series:
\[
\sum_{n=1}^{\infty} \frac{n}{(n^2+1)^2}
\]
**Explanation:**
The Integral Test can be used to determine the convergence of an infinite series. To apply the Integral Test, the function \( f(x) = \frac{x}{(x^2+1)^2} \) needs to be:
1. Positive
2. Continuous
3. Decreasing
on the interval \([1, \infty)\).
1. **Positivity:** The function is positive for \( x \geq 1 \).
2. **Continuity:** The function is continuous for all \( x \geq 1 \), since it's a rational function whose denominator does not equal zero in this interval.
3. **Decreasing Function Check:** To ensure the function is decreasing, compute the derivative \( f'(x) \) and evaluate whether it is negative for \( x \geq 1 \).
If these conditions are satisfied, compute the improper integral:
\[
\int_{1}^{\infty} \frac{x}{(x^2+1)^2} \, dx
\]
If the integral converges, so does the series. If the integral diverges, so does the series.
Expert Solution

arrow_forward
Step 1
Given series,
Integral test:
Suppose that f(x) is a continuous, positive and decreasing function on the interval [n, ) and that fn=an then,
Step by stepSolved in 4 steps

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.Similar questions
- Determine whether the Series is convergent tor dlivergent.Write the exact test that yoU Use. 2n-2 T 9 sin(arrow_forwardFor which z EC does the series En=0 n converge?arrow_forwardState whether the series converges or diverges and justify it using a divergence, integral, basic comparison or limit comparison test.arrow_forward
- Given the series k=0 Does this series converge or diverge? O diverges O converges If the series converges, find the sum:arrow_forwardQ/ which of the following series converge and which diverge? Givereasons for your Answer Σ sechn n=1arrow_forwardUse the Integral Test to determine whether the infinite series is convergent. dx = Σ b. By the Integral Test, the infinite series? 7 a. To perform the Integral Test, one should calculate the following improper integral. If the integral is finite, enter the number. Otherwise, enter -00 or co if the integral is infinite, or enter DNE if the integral does not exist in another way. 6ln narrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning

Calculus: Early Transcendentals
Calculus
ISBN:9781285741550
Author:James Stewart
Publisher:Cengage Learning

Thomas' Calculus (14th Edition)
Calculus
ISBN:9780134438986
Author:Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:PEARSON

Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:9780134763644
Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:PEARSON

Calculus: Early Transcendentals
Calculus
ISBN:9781319050740
Author:Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:W. H. Freeman


Calculus: Early Transcendental Functions
Calculus
ISBN:9781337552516
Author:Ron Larson, Bruce H. Edwards
Publisher:Cengage Learning