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Use the graphical method to break F into components parallel to bars AB and BC. If the component parallel to bar AB is 7 kN, what is the magnitude of F?

Use the graphical method to break F into components parallel to bars AB and BC. If the component parallel to bar AB is 7 kN, what is the magnitude of F?

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Problem 4: Values: a = 300 mm b = 75 mm c = 100 mm Use the graphical method to break F into components parallel to bars AB and BC. If the component parallel to bar AB is 7 kN, what is the magnitude of F? Comments: B This is a perfect example of why the graphical method is useful - we are asked to resolve a force into components that are not perpendicular to one another. It's difficult to apply regular old sine and cosine (i.e. trig) for this because we're not dealing with right triangles. Instead we will use the law of sines and/or the law of cosines. • Start by drawing a vertical line to represent the vector F. Now draw a line parallel to AB passing through the top of F, and another line, also parallel to AB, through the bottom. Repeat for BC. You should have a parallelogram divided into two triangles by the resultant vector F. Pick one of the triangles to work with, use geometry to figure out the angles, and then apply the law of sines to compute the magnitude of F. Remember, these aren't right triangles so you have to use the law of sines. See below...
Transcribed Image Text:Problem 4: Values: a = 300 mm b = 75 mm c = 100 mm Use the graphical method to break F into components parallel to bars AB and BC. If the component parallel to bar AB is 7 kN, what is the magnitude of F? Comments: B This is a perfect example of why the graphical method is useful - we are asked to resolve a force into components that are not perpendicular to one another. It's difficult to apply regular old sine and cosine (i.e. trig) for this because we're not dealing with right triangles. Instead we will use the law of sines and/or the law of cosines. • Start by drawing a vertical line to represent the vector F. Now draw a line parallel to AB passing through the top of F, and another line, also parallel to AB, through the bottom. Repeat for BC. You should have a parallelogram divided into two triangles by the resultant vector F. Pick one of the triangles to work with, use geometry to figure out the angles, and then apply the law of sines to compute the magnitude of F. Remember, these aren't right triangles so you have to use the law of sines. See below...
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