Use the given information to find the number of degrees of​ freedom, the critical values χ2L and χ2R​, and the confidence interval estimate of σ. It is reasonable to assume that a simple random sample has been selected from a population with a normal distribution. Platelet Counts of Women 98% confidence; n = 40, s = 65.2 Df = ____ (Type a whole​ number.) χ2L = ____ ​(Round to three decimal places as​ needed.) χ2R = ____ ​(Round to three decimal places as​ needed.) The confidence interval estimate of σ is ____ < σ <____ ​(Round to one decimal place as​ needed.)

The data in Table represent the population of the statistics students and the marks obtained in the examination on hypothesis tests. Knowing that the previous data are from the population with a normal distributionDetermine:1. Using the T distribution. Make a confidence interval for a 95% confidence level. Alpha mean = .05 enter right value XX.XX Table: 0 0 0 0 0 5 10 15 15 15 20 20 25 25 40 45 50 50 55 75 80 85 90 95 105

67°F Cloudy BIG Corporation advertises that its light bulbs have a mean lifetime, u, of 3000 hours. Suppose we have good reason to believe that u is less than 3000 hours and decide to do a statistical test of the claim. We choose a random sample of light bulbs manufactured by BIG and find that the mean lifetime for this sample is 2840 hours and that the sample standard deviation of the lifetimes is 750 hours. Based on this information, complete the parts below. (a) What are the null hypothesis Ho and the alternative hypothesis H₁ that should be used for the test? 0 H₂:0 H₁ (b) Suppose that we decide not to reject the null hypothesis. What sort of error might we be making? (Choose one) ▼ (c) Suppose the true mean lifetime of BIG's light bulbs is 2820 hours. Fill in the blanks to describe a Type II error. A Type II error would be (Choose one) the hypothesis that u is (Choose one) (Choose one) ▼ when, in fact, μ is (Choose one) Explanation Check 9 DALL μχ 0O #0 Españ ? Aa 2022 McGraw Hill…

Assume that a procedure yields a binomial distribution with n=58n=58 trials and the probability of success for one trial is p=23%p=23%.Find the mean for this binomial distribution.(Round answer to one decimal place.)μ=μ= Find the standard deviation for this distribution.(Round answer to two decimal places.)σ=σ= Use the range rule of thumb to find the minimum usual value μ–2σ and the maximum usual value μ+2σ.Enter answer as an interval using square-brackets only with whole numbers.usual values =