Use the given database to output the results of the following SQL queries: For these queries you need the student, takes, section, and teaches tables. I gave you all the resources you need. a.)  SELECT ∗ FROM Student AS S, Takes AS T WHERE S.ID = T.ID AND T.semester = 'Fall'; b.)  (SELECT S.course id, S.semester, S.year FROM Section AS S WHERE S.room number = 101) INTERSECT (SELECT T.course id, T.semester, T.year FROM Teaches AS T WHERE T.ID = 83821); c.)  SELECT T.course id FROM takes AS T WHERE T.semester IN (SELECT Z.semester FROM teaches AS Z WHERE Z.ID = 10101) OR T.semester IN (SELECT X.semester FROM section AS X WHERE X.time slot id ='B');

Based on SQL query knowledge

WorksOn Database: Employee (EmployeeNumber, EmployeeName, BirthDate, Title, Salary, DepartmentNumber) Project (ProjectNumber, ProjectName, Budget, DepartmentNumber) Department (DepartmentNumber, DepartmentName, ManagerNumber) WorksOn (EmployeeNumber, ProjectNumber, Responsibility, Hours) Questions: 1) Write an SQL query that returns the project number and name for projects with a budget no greater than $1,050,000. 2) Write an SQL query that returns all works on records where hours worked is less than 5 and the responsibility is 'Manager'. 3) Write an SQL query that returns the employees (number and name only) who have a title of 'EE' or 'SA' and make more than $50,000. 4) Write an SQL query that returns the employees (name and salary only) in department 'D1' ordered by decreasing salary. 5) Write an SQL query that returns the departments (all fields) ordered by descending department name.

My SQL WORKBENCH **Please note that you may actually use as many tables as you need. You are not limited to use only twotables.Example:SELECT *FROM DEPARTMENTS;SELECT *FROM EMPLOYEES;Now join departments and employees tables.SELECT FIRST_NAME, DEPARTMENT_NAMEFROM EMPLOYEES, DEPARTMENTSWHERE EMPLOYEES.DEPARTMENT_ID = DEPARTMENTS.DEPARTMENT_ID;NOTE: If you omit the join condition, the result will be the Cartesian Product of the two tables. A CartesianProduct joins all rows of the first table with all rows of the second table.That is if the first table has n rows and the second table has m rows, the output will have n*m rows.The following query will produce a Cartesian Product:SELECT FIRST_NAME, DEPARTMENT_NAMEFROM EMPLOYEES, DEPARTMENTS;**When table names are long, qualifying column names might be very time consuming. Usually peopleprefer to use table aliases for this purpose.Example: List the name of all employees who work for 'Purchasing' departmentSELECT E.FIRST_NAME "EMPLOYEE…

I NEED HELP WITH THIS QUESTION FOR MY DATABASE MANAGEMENT CLASS FOR SQL DEVELOPER 5. Now compute Average GPA in each class. Display class_code, Class_GPA. Assume all courses are 3 credit courses. A general formula for GPA would be sum(gradepoints x Hrs)/sum(Hrs). Here you can just take an average of gradepoints as the credit hours are same for all courses.