Use the given confidence interval to find the margin of error and the sample mean. (15.8,23.6) The sample mean is The margin of error is (Type an integer or a decimal.) (Type an integer or a decimal.)

the night shift workers in three of the super bo's specialty stores stock about 500 products in about 3 hours. how does the rate compare with the stocking done in the other 97 stores in the chain, whixh average about 496 products stocked in 3 hours? are the stockers at the specialty stores doing "better than Average" job? heres the info you need                                    size.      products stocks       standard deviation specialty stores       3.          500.                             12.56 all stores.               100.        496.                          22.13

9 The standard error of the mean is, a 0.881       b 0.735       c 0.612       d 0.510

For the given scenario, determine the type of error that was made if any.(begin by determining the null and alternative hypothesis). A new whitening toothpaste advertises for shades as the mean number of shades the toothpaste whitens your teeth. One user claims that the mean number of shades the toothpaste whitens your teeth is different from four shades. The user conducts a hypothesis test and fails to reject the null hypothesis. Assume that in reality, the mean number of shades the two piece white is your teeth is for shade. Was an error made? If so, what type? A, B, C? A.Yes; type 2 error B.Yes; type 1 error C.No; correct decision

Determine if the following statements are true or false. a. Jane took a sample of n = 100 observations from a population with mean and standard deviation. Mike also took a sample of n = 200 observations from the same population. Then, Mike’s sample mean will be closer to the true population mean than Jane’s sample. b. Jane took a sample of n = 100 observations from a population with mean and standard deviation. Mike also took a sample of n = 200 observations from a population with mean and standard deviation 2. Then, the sample mean from Mike’s sample is more likely to be close to the true mean than the sample mean from Jane’s sample. That is, the probability that X is between 90% and 110% of mean is higher for Mike’s sample than for Jane’s sample.