Use the formula Ỹ - to.05(2),df SE < μ< Ỹ + 10.05(2),df SE to calculate a 95% confidence interval for mean sleep time in the cave population. In the formula, μ is the population mean, Y is he sample mean, to.05(2),df is a two-tailed critical value of the t-distribution with df degrees of freedom, and SE is the standard error of the mean. Use Statistical Table C if necessary. Give your answer as an interval in the form (lower bound, upper bound). Round each of the bounds to one decimal place.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 13PPS
icon
Related questions
Question

please answer!

The evolution of blind cave forms of the fish Astyanax mexicanus is associated with large reductions in the amount of time
spent sleeping. The eyed, surface forms sleep about 800 minutes per 24-hour day (about 13 hours). The accompanying graph
shows the frequency distribution of sleep times per 24 hours for 23 blind individuals from a single cave population (Duboué
et al. 2011). The sample mean is 129.4 and the standard deviation is 147.2. Assume that the sample is a random sample.
10
Frequency
8
2-
0
100 200 300 400 500
Time sleeping (min)
Whitlock & Schluter, The Analysis of Biological Data, 3e © 2020 W. H. Freeman and Company
0
Use the formula
Ỹ - to.05(2),df SE < µ< Ỹ + $0.05(2),df SET
to calculate a 95% confidence interval for mean sleep time in the cave population. In the formula, μ is the population mean, Y is
the sample mean, to.05(2),df is a two-tailed critical value of the t-distribution with df degrees of freedom, and SE is the standard
error of the mean. Use Statistical Table C if necessary.
Give
è your answer as an interval in the form (lower bound, upper bound). Round each of the bounds to one decimal place.
Transcribed Image Text:The evolution of blind cave forms of the fish Astyanax mexicanus is associated with large reductions in the amount of time spent sleeping. The eyed, surface forms sleep about 800 minutes per 24-hour day (about 13 hours). The accompanying graph shows the frequency distribution of sleep times per 24 hours for 23 blind individuals from a single cave population (Duboué et al. 2011). The sample mean is 129.4 and the standard deviation is 147.2. Assume that the sample is a random sample. 10 Frequency 8 2- 0 100 200 300 400 500 Time sleeping (min) Whitlock & Schluter, The Analysis of Biological Data, 3e © 2020 W. H. Freeman and Company 0 Use the formula Ỹ - to.05(2),df SE < µ< Ỹ + $0.05(2),df SET to calculate a 95% confidence interval for mean sleep time in the cave population. In the formula, μ is the population mean, Y is the sample mean, to.05(2),df is a two-tailed critical value of the t-distribution with df degrees of freedom, and SE is the standard error of the mean. Use Statistical Table C if necessary. Give è your answer as an interval in the form (lower bound, upper bound). Round each of the bounds to one decimal place.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 8 images

Blurred answer
Recommended textbooks for you
Glencoe Algebra 1, Student Edition, 9780079039897…
Glencoe Algebra 1, Student Edition, 9780079039897…
Algebra
ISBN:
9780079039897
Author:
Carter
Publisher:
McGraw Hill