Use the following circuit diagram for questions 1-4. The circuit below contains a battery and four resistors. The voltage across the battery is 11.6 V. In the circuit, the values of all the resistances are known. These resistances are - R₁ = 4.9 2, R2 = 2.1 S2, R3 = 6.0 2, R4 = 7.2 2, and R5 = 3.5 2 R₁ =4.9 R2=2.1 R3=6 Ry=1.2 R5:3.5 V B=11.6 R₁ R₁₂ R3 www A notais terit od vd bot (R,+R2 Series 4.9+2.1=72 Γ 7.2 R4 3.5 www R5 R12R3 parlles =.309 R123 = 3.23 1. Obtain the voltage drop across the third resistor R3. 3.23 (a) 2.7 V 5.1 V 7.2. .83×6=4.98 1.6 (c) 1.5 V (d) 6.8 V (e) 3.9 V 11.6-4.98-6.62 to do 2. Obtain the current through the third resistor R3: 3.5 Req 0.03.23+ 7.2 + 3.5=13.93 oltof Req = 13.9 V=IR I= \/ 11.6-83 13.9 Whole circuit A (a) 1.3 A V=IR (b) 1.6 A saq si lo 300 egaq (c) 2.1 A 5269 I (d) 0.45 A 5.6 b 18554 0.80 A ) (2-0)

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Use the following circuit diagram for questions 1-4.
The circuit below contains a battery and four resistors. The voltage across the battery is
11.6 V. In the circuit, the values of all the resistances are known. These resistances are
-
R₁ = 4.9 2, R2 = 2.1 S2, R3 = 6.0 2, R4 = 7.2 2, and R5 = 3.5 2
R₁ =4.9
R2=2.1
R3=6
Ry=1.2
R5:3.5
V
B=11.6
R₁ R₁₂
R3
www
A notais terit od vd bot
(R,+R2 Series
4.9+2.1=72
Γ
7.2
R4
3.5
www
R5
R12R3 parlles
=.309
R123 = 3.23
1. Obtain the voltage drop across the third resistor R3.
3.23
(a) 2.7 V
5.1 V
7.2.
.83×6=4.98
1.6
(c) 1.5 V
(d) 6.8 V
(e) 3.9 V
11.6-4.98-6.62
to do
2. Obtain the current through the third resistor R3:
3.5
Req
0.03.23+ 7.2 + 3.5=13.93
oltof Req = 13.9
V=IR I= \/ 11.6-83
13.9
Whole circuit
A
(a) 1.3 A
V=IR
(b) 1.6 A
saq si lo 300
egaq
(c) 2.1 A
5269
I
(d) 0.45 A
5.6
b
18554
0.80 A
) (2-0)
Transcribed Image Text:Use the following circuit diagram for questions 1-4. The circuit below contains a battery and four resistors. The voltage across the battery is 11.6 V. In the circuit, the values of all the resistances are known. These resistances are - R₁ = 4.9 2, R2 = 2.1 S2, R3 = 6.0 2, R4 = 7.2 2, and R5 = 3.5 2 R₁ =4.9 R2=2.1 R3=6 Ry=1.2 R5:3.5 V B=11.6 R₁ R₁₂ R3 www A notais terit od vd bot (R,+R2 Series 4.9+2.1=72 Γ 7.2 R4 3.5 www R5 R12R3 parlles =.309 R123 = 3.23 1. Obtain the voltage drop across the third resistor R3. 3.23 (a) 2.7 V 5.1 V 7.2. .83×6=4.98 1.6 (c) 1.5 V (d) 6.8 V (e) 3.9 V 11.6-4.98-6.62 to do 2. Obtain the current through the third resistor R3: 3.5 Req 0.03.23+ 7.2 + 3.5=13.93 oltof Req = 13.9 V=IR I= \/ 11.6-83 13.9 Whole circuit A (a) 1.3 A V=IR (b) 1.6 A saq si lo 300 egaq (c) 2.1 A 5269 I (d) 0.45 A 5.6 b 18554 0.80 A ) (2-0)
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