
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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![Use the data to calculate the standard entropy change for the following
reaction:
5.
S°[Mt(s)]
43.2 J/K mol
Mt(s) + ½ O2(g) → MtO(s)
S°[O2(g)] = 305.1 J/K-mol
S°[MtO(s)]
62.6 J/K mol
a) -133.2 J/K
b) -285.7 J/K
c) 285.7 J/K
d) 133.2 J/K](https://content.bartleby.com/qna-images/question/60233bc8-b7a4-4cb1-97f6-a0fef93353db/ef7c8f1d-05b8-4ff3-9d65-9be4bc76d043/44vz2qf_thumbnail.jpeg)
Transcribed Image Text:Use the data to calculate the standard entropy change for the following
reaction:
5.
S°[Mt(s)]
43.2 J/K mol
Mt(s) + ½ O2(g) → MtO(s)
S°[O2(g)] = 305.1 J/K-mol
S°[MtO(s)]
62.6 J/K mol
a) -133.2 J/K
b) -285.7 J/K
c) 285.7 J/K
d) 133.2 J/K
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- Calculate the temperature, in Kelvins, at which the decomposition of calcium carbonate becomes spontaneous (you do not need to include temperature units in your answer): CaCO3 (s) --> CaO (s) + CO2 (g) ΔHo = 179.0 kJ ΔSo = 160.2 J/Karrow_forwardFor a given reaction, ΔH = +31.15 kJ/mol and ΔS = +126.83 J/K · mol. Above what temperature is the reaction is spontaneous?arrow_forwardThe reaction 2 NO(g) ⇆ N2O4(g) occurs at 25oC under standard state conditions with ΔGo = 13.1 kJ/mol. What is the free energy change (in J/mol) when the NO partial pressure is 0.649 Atm and the N2O4 partial pressure is 0.0015 Atm?arrow_forward
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