Use the chi-square test to determine if the listed occupations and personality preferences are independent at the 0.01 level of significance. (a) What is the level of significance? State the null and alternate hypotheses. Ho: Myers-Briggs preference and profession are not independent. H: Myers-Briggs preference and profession are not independent. profession are independent. H: Myers-Briggs preference and profession are independent. profession are not independent. H: Myers-Briggs preference and profession are independent. profession are independent. H: Myers-Briggs preference and profession are not independent. Are all the expected frequencies greater than 5? O Yes No What sampling distribution will you use? uniform chi-square normal binomial (b) Find the value of the chi-square statistic for the sample. (Round the expected frequencies to at least three decimal places. Round the test statistic to three decimal places.) What are the degrees of freedom? Student's t Ho: Myers-Briggs preference and (c) Find or estimate the Pvalue of the sample test statistic. p-value > 0.100 0.050 < p-value < 0.100 0.005 p-value < 0.010 p-value < 0.005 Ho: Myers-Briggs preference and Ho: Myers-Briggs preference and 0.025 a, we fail to reject the null hypothesis. Since the P-value> x, we reject the null hypothesis. Since the P-value s o, we reject the null hypothesis. Since the Pvalues x, we fail to reject the null hypothesis. (e) Interpret your conclusion in the context of the application. At the 1% level of significance, there is insufficient evidence to conclude that Myers-Briggs preference and the profession are not independent. At the 1% level of significance, there is sufficient evidence to conclude that Myers-Briggs preference and the profession are not independent.
Use the chi-square test to determine if the listed occupations and personality preferences are independent at the 0.01 level of significance. (a) What is the level of significance? State the null and alternate hypotheses. Ho: Myers-Briggs preference and profession are not independent. H: Myers-Briggs preference and profession are not independent. profession are independent. H: Myers-Briggs preference and profession are independent. profession are not independent. H: Myers-Briggs preference and profession are independent. profession are independent. H: Myers-Briggs preference and profession are not independent. Are all the expected frequencies greater than 5? O Yes No What sampling distribution will you use? uniform chi-square normal binomial (b) Find the value of the chi-square statistic for the sample. (Round the expected frequencies to at least three decimal places. Round the test statistic to three decimal places.) What are the degrees of freedom? Student's t Ho: Myers-Briggs preference and (c) Find or estimate the Pvalue of the sample test statistic. p-value > 0.100 0.050 < p-value < 0.100 0.005 p-value < 0.010 p-value < 0.005 Ho: Myers-Briggs preference and Ho: Myers-Briggs preference and 0.025 a, we fail to reject the null hypothesis. Since the P-value> x, we reject the null hypothesis. Since the P-value s o, we reject the null hypothesis. Since the Pvalues x, we fail to reject the null hypothesis. (e) Interpret your conclusion in the context of the application. At the 1% level of significance, there is insufficient evidence to conclude that Myers-Briggs preference and the profession are not independent. At the 1% level of significance, there is sufficient evidence to conclude that Myers-Briggs preference and the profession are not independent.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Problem 1P
Related questions
Question
Do parts b,c,d and e
![Use the chi-square test to determine if the listed occupations and personality preferences are
independent at the 0.01 level of significance.
(a) What is the level of significance?
State the null and alternate hypotheses.
Ho: Myers-Briggs preference and profession are not independent.
Hi: Myers-Briggs preference and profession are not independent.
profession are independent.
H: Myers-Briggs preference and profession are independent.
profession are not independent.
H₁: Myers-Briggs preference and profession are independent.
profession are independent.
Hi: Myers-Briggs preference and profession are not independent.
Are all the expected frequencies greater than 5?
Yes No
What sampling distribution will you use?
uniform chi-square normal binomial Student's t
(b) Find the value of the chi-square statistic for the sample. (Round the expected frequencies to at least
three decimal places. Round the test statistic to three decimal places.)
What are the degrees of freedom?
Ho: Myers-Briggs preference and
(c) Find or estimate the P-value of the sample test statistic.
p-value > 0.100 0.050 < p-value < 0.100
0.005< p-value < 0.010 p-value < 0.005
Ho: Myers-Briggs preference and
Ho: Myers-Briggs preference and
0.025 < p-value < 0.050 0.010 < p-value < 0.025
(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis of
independence?
Since the P-value > x, we fail to reject the null hypothesis. Since the P-value > x, we reject the null
]
hypothesis. Since the P-values x, we reject the null hypothesis. Since the P-values x, we fail
to reject the null hypothesis.
(e) Interpret your conclusion in the context of the application.
At the 1% level of significance, there is insufficient evidence to conclude that Myers-Briggs preference
and the profession are not independent. At the 1% level of significance, there is sufficient evidence to
conclude that Myers-Briggs preference and the profession are not independent.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fff072a7d-17de-4b51-9c55-f2704da35c92%2F89e422cf-660f-4c2d-a9ad-6eafe54bf781%2Fye5wdqc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Use the chi-square test to determine if the listed occupations and personality preferences are
independent at the 0.01 level of significance.
(a) What is the level of significance?
State the null and alternate hypotheses.
Ho: Myers-Briggs preference and profession are not independent.
Hi: Myers-Briggs preference and profession are not independent.
profession are independent.
H: Myers-Briggs preference and profession are independent.
profession are not independent.
H₁: Myers-Briggs preference and profession are independent.
profession are independent.
Hi: Myers-Briggs preference and profession are not independent.
Are all the expected frequencies greater than 5?
Yes No
What sampling distribution will you use?
uniform chi-square normal binomial Student's t
(b) Find the value of the chi-square statistic for the sample. (Round the expected frequencies to at least
three decimal places. Round the test statistic to three decimal places.)
What are the degrees of freedom?
Ho: Myers-Briggs preference and
(c) Find or estimate the P-value of the sample test statistic.
p-value > 0.100 0.050 < p-value < 0.100
0.005< p-value < 0.010 p-value < 0.005
Ho: Myers-Briggs preference and
Ho: Myers-Briggs preference and
0.025 < p-value < 0.050 0.010 < p-value < 0.025
(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis of
independence?
Since the P-value > x, we fail to reject the null hypothesis. Since the P-value > x, we reject the null
]
hypothesis. Since the P-values x, we reject the null hypothesis. Since the P-values x, we fail
to reject the null hypothesis.
(e) Interpret your conclusion in the context of the application.
At the 1% level of significance, there is insufficient evidence to conclude that Myers-Briggs preference
and the profession are not independent. At the 1% level of significance, there is sufficient evidence to
conclude that Myers-Briggs preference and the profession are not independent.
Transcribed Image Text:4
The following table shows the Myers-Briggs personality preferences for a random sample of 519 people
in the listed professions. T refers to thinking and F refers to feeling.
Occupation
Clergy (all denominations)
M.D.
Lawyer
Column Total
Personality Type
F
T
62
74
124
260
86
85
88
259
Row Total
148
159
212
519
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