Use technology to construct the confidence intervals for the population variance o and the population standard deviation o. Assume the sample is taken from a normally distributed population. c=0.90, s = 12.25 , n 25 %3D The confidence interval for the population variance is (. (Round to two decimal places as needed.) The confidence interval for the population standard deviation is ( D. (Round to two decimal places as needed.)

Assume that adults have IQ scores that are normally distributed with a mean of 95.2, and a standard deviation of 22.2 Find the first quartile Q1, which is the IQ score separating the bottom​ 25% from the top​ 75%. Can you please provide step by step using the T1-84 plus calculator.   I keep getting stuck on locating the z-score.  I know the first Q is .25  If you use the formula, please provide the actual figures including a picture- so I have a well-rounded answer to this question.   Thank you

n1=16 x‾1=124 s1=35   n2=12 x‾2=86 s2=31 Use this data to find the 98% confidence interval for the true difference between the population means. Assume that the population variances are not equal and that the two populations are normally distributed. Copy Data Step 2 of 3 :   Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places. Step 3 of 3 : Please also find the high and low endpoints and round to four decimal points.

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