
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Question
Use standard reduction potentials to calculate the equilibrium constant for the reaction:
2Ag+(aq) + Pb(s) → 2Ag(s) + Pb2+(aq)
Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm.
Equilibrium constant: _____
G° for this reaction would be _________ (greater or less) than zero.

Transcribed Image Text:Sometimes the base-10 logarithm is used and the substitution of 2.303 log for In is made. (2.303 × 0.0257 = 0.0592) Then, the equation
for base-10 logs at 25 °C is:
0.0592
E°
cell
log K
base-10 logarithm
n
A common student error is to use the wrong kind of logarithm. Be sure, when you choose an equation, to use the correct logarithm.

Transcribed Image Text:Relationship between E°cell and K
The equilibrium constant for a cell reaction can be calculated from the standard cell voltage. The relationship between them is:
RT
E°.
cell
- In K
nF
where
standard cell potential
ideal gas constant
T = kelvin temperature
n = number of moles of electrons for the reaction as written
F = charge carried by 1 mol of electrons
K = equilibrium constant
E°
R
%3D
It is customary to use the equation in a form where numerical values are substituted for R, T and F at a temperature of 25 °C.
For
R = 8.314 J molr'K!
T =
298.15 K
F
96,485 J V' mol"1
(8.314 J moll K)(298.15 K)
RT
= 0.0257 V
F
96,485 J V' mol"
and the equation with the potential in volts is:
0.0257
E° cell
In K
natural logarithm
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