Use power series to solve the initial-value problem Answer: y = ∞0 n=0 ²n + 8 72=() y" + 3xy' + 3y = 0, x2n+1 y(0) = 1, y' (0) = 0

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Using Power Series to Solve the Initial-Value Problem**

We are tasked with solving the following initial-value problem using a power series approach:

\[ y'' + 3xy' + 3y = 0, \]
\[ y(0) = 1, \]
\[ y'(0) = 0. \]

**Solution:**

We express the solution \( y \) as a power series:

\[ y = \sum_{n=0}^{\infty} a_n x^n + x^2 \sum_{n=0}^{\infty} a_n x^{2n+1}. \]

This form allows for solving the differential equation and applying the given initial conditions.
Transcribed Image Text:**Using Power Series to Solve the Initial-Value Problem** We are tasked with solving the following initial-value problem using a power series approach: \[ y'' + 3xy' + 3y = 0, \] \[ y(0) = 1, \] \[ y'(0) = 0. \] **Solution:** We express the solution \( y \) as a power series: \[ y = \sum_{n=0}^{\infty} a_n x^n + x^2 \sum_{n=0}^{\infty} a_n x^{2n+1}. \] This form allows for solving the differential equation and applying the given initial conditions.
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